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DENIUS [597]
3 years ago
15

Find the value of y.

Mathematics
1 answer:
docker41 [41]3 years ago
3 0
76! its because its a vertical to the other 76
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Help me please , will mark brainliest
NISA [10]

Answer:

10

Step-by-step explanation:

diameter is half of radius

7 0
3 years ago
Solve the inequality. Graph the solution.<br> 7z&lt; -28
Zepler [3.9K]

Answer: The answer is -9

Step-by-step explanation:

7z<-28= -9

Because we take the -28 and add 19 because that's the common denominator and we come up with -9

6 0
3 years ago
Points frreeeeeeeeeeeee :)
Gala2k [10]

Answer:

thx m8

Step-by-step explanation:

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7 0
2 years ago
Read 2 more answers
. Quantas senhas com 4 algarismos diferentes podemos escrever com os algarismos 1, 2, 3, 4, 5, 6?
ruslelena [56]

Answer:

We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

Step-by-step explanation:

We have to find how many passwords with 4 different digits can we write with the numbers 1, 2, 3, 4, 5, and 6.

Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.

Since we are given six numbers (1, 2, 3, 4, 5, and 6) and have to make 4 different digits passwords.

  • Now, for first digit of the password, we have 6 possibilities (numbers from 1 to 6).
  • Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).
  • Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).
  • Similarly, for the fourth digit of the password, we have 3 possibilities (because three numbers from 1 to 6 have been used above and they can't be repeated).

So, the number of passwords with 4 different digits we can write = 6 \times 5 \times 4 \times 3  = 360 possibilities.

Hence, we can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

4 0
3 years ago
A quality control expert found 12 defective cell phones in a shipment of 75 cell phones, based on these results how many cell ph
mart [117]

Answer:

240 cell phones

Step-by-step explanation:

=12×1500

=18000÷75

=240

8 0
2 years ago
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