Describe how electricity moves through wires

1 answer:

8 0

The particles that carry charge through wires in a circuit are mobile electrons. The electric field direction within a circuit is by definition the direction that positive test charges are pushed. Thus, these negatively charged electrons move in the direction opposite the electric field.

You might be interested in

HELLPPPPP 5th grade math

irakobra [83]

Energy inputs, outputs and losses are summarized below:

Input - Chemical energy/Output - Luminous energy/Losses - Hystheresis-related dissipation.
Input - Fluid energy, heat/Output - Translational mechanical energy/Losses - Waste energy.
Input - Translational mechanical energy/Output - Rotational mechanical energy/Losses - Friction-related work.
Input - Electric energy/Output - Translational and rotational mechanical energy/Losses - Power dissipation, drag-related work.
Input - Translational and rotational mechanical energy/Output - Translational mechanical energy/Losses - Friction-related work, drag-related work.
Input - Fluid energy, heat/Output - Translational and rotational mechanical energy/Losses - Waste energy, friction-related work and drag-related work.

<h2>Procedure - Application of the principle of energy conservation</h2><h2 /><h3>Introduction</h3><h3 />

In this question we must apply the definition of the principle of energy conservation to each case, understanding what kind of <em>energy</em> inputs ( $E_{in}$ ) and outputs exists ( $E_{out}$ , $E_{loss}$ ).

We proceed to apply a simplified scheme, on the assumption that each system works at <em>steady</em> state, in which we shall construct each answer:

$E_{in} - E_{out} - E_{l} = 0$ (1)

Where:

$E_{in}$ - Energy input.
$E_{out}$ - Energy output.
$E_{l}$ - Energy losses.

<h3>Case analysis</h3>

Now we proceed to summarize the inputs, outputs and losses for each case:

<h3><em>Flashlight</em></h3>

Input - Chemical energy (battery)/Output - Luminous energy (screen)/Losses - Hystheresis-related dissipation (battery)

<h3><em>Hot air balloon</em></h3>

Input - Fluid energy (fuel), heat (ignition)/Output - Translational mechanical energy (Buoyancy force)/Losses - Waste energy (smog)

<h3><em>Water wheel</em></h3>

Input - Translational mechanical energy (water flow)/Output - Rotational mechanical energy (wheel)/Losses - Friction-related work (bearings, etc)

Input - Electric energy (current)/Output - Translational and rotational mechanical energy (wind)/Losses - Power dissipation (AC engine/cables), drag-related work (interaction between air and fan)

<h3><em>Hitting a golf ball</em></h3>

Input - Translational and rotational mechanical energy (arm)/Output - Translational mechanical energy (ball)/Losses - Friction-related work (Human body, interactions between player and ball), drag-related work (interactions between ball and air)

<h3><em>Motorcycle</em></h3>

Input - Fluid energy (fuel), heat (ignition)/Output - Translational and rotational mechanical energy (motorcycle and driver)/Losses - Waste energy (smog), friction-related work (interaction between tires and ground) and drag-related work (interactions between driver, motorcycle and surrounding air)

To learn more on energy conversion, we kindly invite to check this verified question: brainly.com/question/11234965

5 0

2 years ago

When the phenol shown below is treated with KOH, it forms a product whose IR spectrum does not show an absorption in the 3200-36

AlladinOne [14]

Answer:

Explanation:

The first attached diagram shows the proposed phenol that is being treated with KOH to form Oxonine (CₐHₐO).

Reaction of Arylhalide after treatment with KOH lead to the displacement of Bromine atom with the hydrogen from the hydroxyl (OH) substituent , then forming HBr , leaving the oxy (-O) atom alone to form an Oxonine compound.

Therefore the propose structure for the product (Oxonine) CₐHₐO is shown in the second diagram attached below.