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garik1379 [7]
3 years ago
8

What is the name of the molecule shown below?

Chemistry
1 answer:
DiKsa [7]3 years ago
8 0

Answer:

the correct awnser is b 1-heptene

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A flash contains 85.6g of C7H5NO3S (Saccharine) in 2.00 litre of a solution. What is the molarity?
larisa86 [58]

Answer:

0.234 M

Explanation:

C- 12.009 x 7

H- 1.001 x 5

N- 14.006

O- 16 x 3

S- 32.059

___________+

183.133 g/mol

\frac{1mol}{183.133g} *\frac{85.6g}{2.00L}  = 0.234 M Cancel out the grams mol/L equals molarity. Lowest significant figure is 3

7 0
3 years ago
If 190dm of hydrogen gas collected at 20°c and 760mmHg .Calculate it's volume at stp (standard pressure=760mmHg
Andrei [34K]

Answer:

177.1 L

Explanation:

The excersise can be solved, by the Ideal Gases Law.

P . V = n . R . T

In first step we need to determine the moles of gas:

We convert T° from, C° to K → 20°C + 273 = 293K

We convert P from mmHg to atm → 760 mmHg = 1atm

1Dm³ = 1L → 190L

We replace: 190 L . 1 atm = n . 0.082 . 293K

(190L.atm) / 0.082 . 293K = 7.91 moles.

We replace equation at STP conditions (1 atm and 273K)

V = (n . R .T) / P

V = (7.91 mol . 0.082 . 273K) / 1atm = 177.1 L

We can also make a rule of three:

At STP conditions 1 mol of gas occupies 22.4L

Then, 7.91 moles will be contained at (7.91 . 22.4) /1 = 177.1L

3 0
3 years ago
Please help me. How do I do ideal gas law?
Tcecarenko [31]
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
4 0
3 years ago
I need help with 2. I’ll give brainliest
noname [10]

Answer:

Lines of latitude run from east to west.

Explanation:

8 0
3 years ago
HELP PLEASE! <br> Picture for question provided
BartSMP [9]

Answer:

Explanation:

The first one is CrO.  The Chromium has the same charge as the oxygen so mol numbers are dropped.

The Second one is CrO2 The two oxygens have a charge of 2(-2) = -4. To balance this, the Chromium must have a charge of +4 Cr(Iv)O2

The third one is can be set up like this

Cr + 3(-2) = 0

Cr - 6 = 0

Cr = 6

Therefore the formula is Cr(vi)O3

The last one is a bit tricky. Follow this carefully. There are 2 Crs and 3Os.

The formula looks like this

2Cr + 3(-2) = 0

2Cr - 6 = 0

2Cr = 6

Cr = 3

The formula is Cr(iii)2 O3

5 0
2 years ago
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