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garik1379 [7]
3 years ago
8

What is the name of the molecule shown below?

Chemistry
1 answer:
DiKsa [7]3 years ago
8 0

Answer:

the correct awnser is b 1-heptene

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Water changes from a liquid to a gas in the process of evaporation. <br> true or false
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This it true because in the triangle of the transformation from solid, liquid, and gas
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Sodium carbonate is commonly known as washing soda and is used in detergents as a water softener. What is the molarity of 5.30 g
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2 years ago
Both kepler's laws and newton's laws tell us something about the motion of the planets, but there are fundamental differences be
I am Lyosha [343]

Answer: See description

Explanation:

Kepler's laws have three principal points:

1. planets orbit the sun in elliptical paths

2. the orbial period is related to the orbital distance by T^{2} = d^3

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Newton:

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3 years ago
Our day is 24 hours long because that is the time it takes the earth to
Marianna [84]
Complete one rotation. 

Hope this helps.
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3 years ago
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The table shows the amount of radioactive element remaining in a sample over a period of time.
Assoli18 [71]

It would take 147 hours for 320 g of the sample to decay to 2.5 grams from the information provided.

Radioactivity refers to the decay of a nucleus leading to the spontaneous emission of radiation. The half life of a radioactive nucleus refers to the time required for the nucleus to decay to half of its initial amount.

Looking at the table, we can see that the initial mass of radioactive material present is 186 grams, within 21 hours, the radioactive substance decayed to half of its initial mass (93 g). Hence, the half life is 21 hours.

Using the formula;

k = 0.693/t1/2

k = 0.693/21 hours = 0.033 hr-1

Using;

N=Noe^-kt

N = mass of radioactive sample at time t

No = mass of radioactive sample initially present

k = decay constant

t = time taken

Substituting values;

2.5/320= e^- 0.033 t

0.0078 = e^- 0.033 t

ln (0.0078) = 0.033 t

t = ln (0.0078)/-0.033

t = 147 hours

Learn more: brainly.com/question/6111443

7 0
2 years ago
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