All categories

3 years ago

Please helpppp !!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!

Mathematics

1 answer:

Tresset [83]3 years ago

5 0

Answer:15

Step-by-step explanation: So we have this triangle but it's not a right triangle right so we can't just Pythagorean theorem our way out. So we have to treat the sizes as ratios. 2:12 is the ratio of the smaller triangle. 12 increases to 78 which means side 2 has to increase as well by the same ratio so 78/12 = 6.5 and 6.5*2=13 so PQ is 13 and to find NQ just add NP and PQ or 2+13 = 15

Hope it helps :)

You might be interested in

In a class 27 of students, 12 have a cat and 11 have a dog. There are 5 students who have a cat and a dog. What is the probabili

frosja888 [35]

Answer:

41.67% probability that a student has a dog given that they have a cat

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: having a cat.

Event B: having a dog.

12 of 27 students have a cat:

This means that $P(A) = \frac{12}{27}$

5 students who have a cat and a dog.

This means that $P(A \cap B) = \frac{5}{27}$

What is the probability that a student has a dog given that they have a cat?

$P(B|A) = \frac{\frac{5}{27}}{\frac{12}{27}} = \frac{5}{12} = 0.4167$

41.67% probability that a student has a dog given that they have a cat

6 0

3 years ago

Find the equation of a line passing through the point (6,−5) and parallel to the line y = 7x + 1. answers : y = 7x − 47 y = −17x

Elan Coil [88]

Answer:

Step-by-step explanation:

$y = 7x + 1.\\(6,-5)\\m= 7\\x1= 6\\y1 = -5\\y-y1=m(x-x1)\\y-(-5) = 7(x-6)\\y+5=7x-42\\y=7x-42-5\\y = 7x-47$

3 0

3 years ago

Idk how to solve 0=4+n over 5

miv72 [106K]

0=4+n over 5
In number form the equation is
 $0= \frac{4+n}5}$

We want to isolate n, so to undue division we multiply, we'll multiply each side by 5 Leaving the equation as
 $0=20+n$

Next we'll subtract 20 from each side to isolate n
The equation would now be
 $-20=n$

So the answer is N=-20

5 0

3 years ago

EF is the median of trapezoid ABCD.

BARSIC [14]

Answer:

Part A) $x = 11$

B) length of BC = x + 12 = x + 12 = 11 + 12 =23

length of EF = 4x - 18 = 4(11) - 18 = 44 - 18 =26

length of AD = 3x - 18 = 3(11) - 4 = 33 - 4 =29

Step-by-step explanation:

Median of trapezium is $m=\frac{base1+base2}{2}$

In provided figure, base1 is x+12 and base2 is 3x-4

A) solve for value of x

calculate the median $m=\frac{base1+base2}{2}$

$4x-18=\frac{x+12+3x-4}{2}$

$4x-18=\frac{4x+8}{2}$

$4x-18=2x+4$

$2x-18=4$

$2x = 18 + 4$

$2x = 22$

$x = 11$

B) To find the length of BC, AD and EF , put the value of x in equation of lines

length of BC = x + 12 = x + 12 = 11 + 12 =23

length of EF = 4x - 18 = 4(11) - 18 = 44 - 18 =26

length of AD = 3x - 4 = 3(11) - 4 = 33 - 4 =29

5 0

3 years ago

Please show me step by step so I can learn to explain it to my son.

aleksklad [387]

These are the steps:
1. Find the area of the trapezium {Whole figure).
2. FInd the area of the rectangle (unshaded).
3. Area of the shaded = Area of trapezium - Area of the rectangle.

Step 1: Find the area of the trapezium:

Formula : Area of trapezium = 1/2 (a + b)h

Area = 1/2 ( 25 + 15) (12) = 240 yd²

Step 2 : Find the area of the rectangle:

Formula : Area = Length x Width

Area = 12 x 3 = 36 yd²

Step 3: Find the shaded region:

240 - 36 = 204 yd²

Answer: 204 yd²

6 0

3 years ago