A stone dropped from a bridge strikes the water 2.2 s later. How high is the bridge above thewater
2 answers:
Distance = ut+1/2gt^2
u is initial velocity g acceleration due to gravity t is time in seconds
u=0, t=2.2 g=9.8
distance = 0.5(9.8)(2.2)^2=23.716
Let the only force acting on the ball is the gravity (free-failing) and the ball was initially stationary
vo = 0
s = vot + 1/2 gt^2
s = 1/2 x 10 x (2.2) ^2 = 24.2 m
You might be interested in
I think this is correct:
Answer:
0.1kg×m3
0.1kgM3
Now,
7kg/s × 5m/s
35kg2Ms
Answer:
1,665.25 km
Step-by-step explanation:
The answer is going to be v= 4500ft3;S=900ft2
Answer:
1.) There are twice as many girls as there are boys in a sixth grade class.
2.) There are half as many boys as there are girls in a sixth grade class.
