A stone dropped from a bridge strikes the water 2.2 s later. How high is the bridge above thewater

2 answers:

8 0

Distance = ut+1/2gt^2
u is initial velocity g acceleration due to gravity t is time in seconds

u=0, t=2.2 g=9.8
distance = 0.5(9.8)(2.2)^2=23.716

vivado [14]3 years ago

3 0

Let the only force acting on the ball is the gravity (free-failing) and the ball was initially stationary
vo = 0

s = vot + 1/2 gt^2

s = 1/2 x 10 x (2.2) ^2 = 24.2 m

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docker41 [41]

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I need help urgent plz someone help me solved this problem! Can someone plz help I’m giving you 10 points! I need help plz help

VMariaS [17]

Answer: a) 8.779 years

b) 8.664 years

<u>Step-by-step explanation:</u>

$A=P\bigg(1+\dfrac{r}{n}\bigg)^{nt}$

A: accumulated amount (balance)
P: principal amount (original/initial investment)
r: interest rate (convert to a decimal)
n: number of times compounded per year
t: number of years

Given: A = 1800, P = 900, r = 8% = 0.08, n = 3, t = unknown

$1800=900\bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\2=\bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\ln\ 2=ln \bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\ln\ 2=3t\ ln\bigg(1+\dfrac{0.08}{3}\bigg)\\\\\\\dfrac{ln\ 2}{3\ ln\bigg(1+\dfrac{0.08}{3}\bigg)}=t\\\\\\\large\boxed{8.779=t}$