Step-by-step explanation:
Let
= mass of the painter
= mass of the scaffold
= mass of the equipment
= tension in the cables
In order for this scaffold to remain in equilibrium, the net force and torque on it must be zero. The net force acting on the scaffold can be written as
Set this aside and let's look at the net torque on the scaffold. Assume the counterclockwise direction to be the positive direction for the rotation. The pivot point is chosen so that one of the unknown quantities is eliminated. Let's choose our pivot point to be the location of . The net torque on the scaffold is then
Solving for T,
or
![T = \frac{1}{9}[m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})]](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B1%7D%7B9%7D%5Bm_sg%281.9%5C%3A%5Ctext%7Bm%7D%29%20%2B%20m_pg%284.2%5C%3A%5Ctext%7Bm%7D%29%5D)
To solve for the the mass of the equipment , use the value for T into Eqn(1):
Answer:
answer deleted again
Step-by-step explanation:
Answer:
Step-by-step explanation:
d and r are the diameter and radius, respectively.
d = 8 units
r = 8/2 = 4 units
area = πr² = 16π square units.
Probability is expressed as
number of favourable outcomes/total number of possible outcomes
Looking at the given scenario, the number os students that earned a grade of A is 5. Since we are concerned with these students, then, the number of favourable outcomes is 5.
The total number of students for all grades is 35. This means that the total number of possible outcomes is 35
Thus, the probability that a student earns a grade of A is
5/35
= 0.14
1468.8/3 = 489.3 in
convert answer into yards (divide by 36)
there was 13.6 yards of fabric in each roll.
