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frutty [35]3 years ago

7 0

Answer:

esfgkjfvgghhhhhhjjhhhhhgfffghjjkkokkkjrdgsgegfggy

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Katena32 [7]

Answer:

(a)

$5^{-3}=\frac{1}{125}$

(b)

$-5^{-3}=-\frac{1}{125}$

(c)

$(-5^{-3})^{-1}=-125$

(d)

$(-5^{-3})^{0}=1$

Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

$5^{-3}=\frac{1}{125}$ ........Answer

(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

4 0

3 years ago

Suma dintre dublul primului numar si triplul celui de-al doilea numar este 117.Primul numar este de trei ori mai mare decat al d

nydimaria [60]

2a+3b=117
a=3b
6b+3b=117==> b=13 ==> a=39

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3 years ago

I'm new to the app. Stumped on all of these

nekit [7.7K]

What are you stumped on?

3 0

3 years ago

What is the value of the expression 3^−4 ?

ikadub [295]

3^-4 = 1/3^4 = 1/81

hope it helps!

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3 years ago

Read 2 more answers

There are no more than 7 peaches in the bowl

stiks02 [169]

P < or = 7.

P could be 7, 6, 5, 4, 3, 2, 1, or zero.

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3 years ago