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GrogVix [38]
3 years ago
7

What happens to gas elements when they reach their melting point??

Chemistry
1 answer:
Zepler [3.9K]3 years ago
4 0

Answer:

<h3 /><h3>Solid</h3>

Explanation:

<h2>❣️♡ jess bragoli ♡❣️</h2>

#<em>k</em><em>e</em><em>e</em><em>p</em><em> </em><em>learning</em><em>!</em><em>!</em>

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Liters of a 2.40 M
kotykmax [81]

Answer:

1.42 L

Explanation:

Step 1:

The following data were obtained from the question :

Molarity of KBr = 2.40 M

Mole of KBr = 3.40 moles

Volume of solution =?

Step 2:

Determination of the volume of the solution.

Molarity of solution is simply the mole of the solute per unit volume the of solution. It is given as :

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 3.4/2.4

Volume = 1.42 L

Therefore, the volume of the solution is 1.42 L

6 0
3 years ago
Calculate the molar mass of carbon tetrafluoride (CF4) in grams per mole, rounding to proper significant figures, if mc= 12.01 u
Nata [24]

Answer:

molar mass of carbon tetrafluoride (CF4) is

(12.01 × 1 ) + ( 4 × 19.00)

= 12.01 + 76

= 88.01u

= 88u

Hope this helps

3 0
3 years ago
Read 2 more answers
650. J is the same amount of energy as A. 155 cal. B. 2720 calC. 650 cal.D. 1550 cal.
sladkih [1.3K]

Answer:

A\text{ : 155 cal}

Explanation:

Here, we want to convert J to cal

Mathematically:

1\text{ cal = 4.186 J}

Thus, to get our answer in cal, we divide the value given by 4.186

We have that as:

\frac{650}{4.186}\text{ = 155 cal}

5 0
2 years ago
HOLMIUM
Sophie [7]

Answer:

1. The graph where x axis and y axis are present is called coordinate.

4. 18

8 0
3 years ago
For the reaction so3 + h2o h2so4, calculate the percent yield if 500. g of sulfur trioxide react with excess water to produce 57
Lelu [443]
The %  yield  if  500 g of  sulfur trioxide  reacted  with  excess  water to   produce  575 g  of  sulfuric  acid is calculated using  the  below  formula


%  yield = actual  yield/ theoretical  yield  x100

actual  yield =575 grams
to  calculate  theoretical  yield
find the  moles  of SO3   used =mass/molar  mass
=  500g/   80 g/mol =6.25  moles

SO3+H2O=H2SO4
by   use of  mole ratio  of SO3  :  H2SO4 which  is 1:1  the moles of H2SO4  is  also=  6.25  moles

the theoretical  yield of H2SO4 is therefore =  moles /molar  mass
=  6.25  x98=  612.5 grams

%yield  is therefore= 575 g/612 g   x100=  93.9  %

5 0
3 years ago
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