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3 years ago

What do you think happens to the matter in a food sample as it is burned?

1 answer:

6 0

Burning and other changes in matter do not destroy matter. The mass of matter is always the same before and after the changes occur. The law of conservation of mass states that matter cannot be created or destroyed

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Connie was making sodium chloride by adding an acid to an alkali. She followed the progress of the reaction with a pH sensor. At

Misha Larkins [42]

⇒Answer:

When the pH sensor hits pH=7.

⇒Explanation:

Because pH=7 is the indicator that the acid and alkali have been neutralized.

5 0

2 years ago

Indigenous rocks form by the cooling and hardening of melted rock.* True False

salantis [7]

Answer: True

Explanation: They are formed by the cooling and hardening of molten magma

3 0

3 years ago

Does ecstasy drug effect how long you live?

const2013 [10]

Answer:

yes it gives some bad effect

Explanation:

6 0

2 years ago

How many moles are equal to 7.62 x 1025 molecules lithium hydroxide

ycow [4]

No of moles:-

$\\ \tt\longmapsto \dfrac{No\:of\:atoms}{Avagadro's\; number}$

$\\ \tt\longmapsto \dfrac{7.62(10^{25})}{6.022(10^{23})}$

$\\ \tt\longmapsto 126.5mol$

8 0

2 years ago

Part a use these data to calculate the heat of hydrogenation of buta-1,3-diene to butane. c4h6(g)+2h2(g)→c4h10(g)

Reptile [31]

<u>Answer:</u> The heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_{(product)}]-\sum [n\times \Delta H_{(reactant)}]$

For the given chemical reaction:

$C_4H_6(g)+2H_2(g)\rightarrow C_4H_{10}(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(1\times \Delta H_{(C_4H_{10})})]-[(1\times \Delta H_{(C_4H_6)})+(2\times \Delta H_{(H_2)})]$

We are given:

$\Delta H_{(C_4H_{10})}=-2877.6kJ/mol\\\Delta H_{(C_4H_6)}=-2540.2kJ/mol\\\Delta H_{(H_2)}=-285.8kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(1\times (-2877.6))]-[(1\times (-2540.2))+(2\times (-285.8))]\\\\\Delta H_{rxn}=234.2J$

Hence, the heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

4 0

2 years ago