<span>The addition of water affect the acidity of a highly acidic solution having pH 2 by increasing the pH level making it more neutral. This is because the concentration of the hydronium ions decreases as more water is added to the solution.</span>
The question is incomplete, the complete question is:
Which option is a microscopic property that helps determine whether or not two substances will dissolve with each other? (1 point)
A. state of matter
B. volume
C. molecular mass
D. polarity
The microscopic property that helps determine whether or not two substances will dissolve with each other is polarity.
A molecule is said to be polar if that molecule possesses a dipole moment. This also means that the molecule has a positive end and a negative end. A typical example of such a molecule is water.
In chemistry, the general rule is that like dissolves like. A polar substance dissolves a polar substance and vice versa.
Therefore we can see that, a microscopic property that helps determine whether or not two substances will dissolve with each other is polarity.
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Answer: The metal that has a greater reactivity is more easily oxidized.
Explanation:
Oxidation is when the elements lose electrons and increase their oxidation state.
The metals tend to react by losing electrons and form the corresponding cation.
For expample, sodium (an alkalyne metal) loses one elecron and form the cation Na¹⁺ , then this cation combine with an anion and form compounds like NaCl, NaOH. The same do the other alkalyne metals.
Magnesium (an alkalyne earth metal) loses two electrons and form the cation Mg²⁺, then it combines with some anions to form compounds, like MgSO₄, Mg(OH)₂.
So, the easier the metal gets oxidized the greater its reactivity.
Answer:
<span>In the addition of hbr to 1-butyne the electrophile in the first step of the mechanism is <u>Hydrogen atom of HBr</u>.
Explanation:
In this reaction first of all HBr approaches the triple bond. A Pi Complex (weak inter-molecular interactions) is formed between the two molecules. And the triple bond attacks the partial positive hydrogen atom creating a negative charge on Bromine along with positive charge on itself (Sigma Complex). In second step the negative Bromide attacks the positive carbon of Butyne.</span>
