What do you think happens to the matter in a food sample as it is burned?

1 answer:

6 0

Burning and other changes in matter do not destroy matter. The mass of matter is always the same before and after the changes occur. The law of conservation of mass states that matter cannot be created or destroyed

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Can someone help me with this

Flura [38]

Answer:

I don't know how to get the answer sorry

Explanation:

6 0

3 years ago

How can you drop two eggs the fewest amount of times, without them breaking? Whoever gets this right I will mark them brainlyest

Alekssandra [29.7K]

Answer:

Okay well simply drop it from one inch on to the ground and it won't break and you could put it into a basket with bubble wrap.

Explanation:

Well if you wrap the egg into bubble wrap a few times them put it into a basket (its your choice) then it won't break because the bubble wrap will just pop a few times but sometimes it depends on where you are dropping it from.

Have a blessed day bye! ;)

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3 years ago

Question 10

bixtya [17]

The reaction that should be followed is
Na2SO4 + C<span>a(NO3)2 --> CaSO4 + 2NaNO3</span>
first calculate the limiting reactant
mol Na2SO4 = 0.075 L (<span>1.54×10−2 mol / L) = 1.155x10-3 mol

mol Ca(NO3)2 = 0.075 L (</span><span>1.22×10−2 mol / L) = 9.15x10-4 mol
so the limiting reactant is the Ca(NO3)2

so all of the Ca2+ will be precipitated, percentage unprecipitated = 0.00 % </span>

5 0

3 years ago

How many moles are in 3.45 g of Ba(CIO3)2 ?

topjm [15]

<h3>Answer:</h3>

0.0113 mol Ba(ClO₃)₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structures</u>

Reading a Periodic Table
Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.45 g Ba(ClO₃)₂

<u>Step 2: Identify Conversions</u>

Molar Mass of Ba - 137.33 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Ba(ClO₃)₂ - 137.33 + 2(35.45) + 6(16.00) = 304.33 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 3.45 \ g \ Ba(ClO_3)_2(\frac{1 \ mol \ Ba(ClO_3)_2}{304.33 \ g \ Ba(ClO_3)_2})$
Multiply/Divide: $\displaystyle 0.011336 \ mol \ Ba(ClO_3)_2$