Answer:
for combustion of naphthalene is -5164 kJ/mol
Explanation:

where, C refers heat capacity and
refers change in temperature.
Here, 
So, 
is generally expressed in terms of per mole unit of reactant. Also,
should be negative as it is an exothermic reaction (temperature increases).
Molar mass of naphthalene is 128.17 g/mol
So, 1.025 g of naphthalene =
of naphthalene
= 0.007997 moles of naphthalene

The stable milk because it stable
A is the answer
Hope it helps :)
Answer:
Opaque → a.no light travels through the material; all light is reflected or absorbed
Translucent → b.some light travels through the material and the image cannot be seen clearly
Transparent → c.all light travels through the material and the image can be seen clearly
Explanation:
Hope this helps :)
Answer:2C12
Explanation:because if u divide the the equation by 2 u well get the same answer you can multiply but that will take longer with the invisible zeros and stuff like that but the answer is 2c12 and on the real FSA u can pull out ur phone and cheat just make sure the teacher is not watching just playing with you DONT DO THAT YOU WILL GET IN SERIOUS TROBLE KIDS DO NOT DO THIS KN THE REAL DAY OF THE FSA PLEASE DONT DO IT YOU WILL GET IN SERIOUS TROUBLE WELL THATS IT FOR TODAY SO HAVE A GREAT DAY THIS IS TO PUT PRESSURE ON YOU