Answer:
UT + CV = 4x + 33
Step-by-step explanation:
Given:
TW = 14
WU = 2x + 2
VW = 2x + 5
WC = 12
Find:
UT + CV
Computation:
UT = TW + WU
UT = 14 + 2x + 2 = 16 + 2x
CV = VW + WC
CV = 2x + 5 + 12 = 2x + 17
UT + CV
16 + 2x + 2x + 17
UT + CV = 4x + 33
Answer:
2789/36 is 77
with a remainder of 17
Step-by-step explanation:
with that template in mind.
since the original or "parent" function is y = x²−4x+3, if we change the "x" argument to "x-2", we end up with a horizontal shift.
the x-2 part would be in the template the Bx+C part, with B = 1 and C = -2, or a horizontal shift to the right of 2/1 or 2 units.
since the parent function has a point at (2, -1), if we move that horizontally only to the right, we'd end up at (4, -1).
Answer:
no, because for x=-3, y would have to be -31
Step-by-step explanation:
boy oh boy (or girl oh girl) - you wrote this in a horrible, horrible format.
I can only guess what your problem and the fitting answer would be.
y = -2×x^2 + 3×x - 4
-4 = -2×(-3)^2 + 3×(-3) - 4
-4 = -2×9 - 9 - 4
-4 = -18 - 9 - 4
-4 = -31
and that is wrong. for (-3,-4) to be on the graph of the function, y would have to be -4 when using x=-3 in the function. but y = -31 for x= -3.
