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mr Goodwill [35]
3 years ago
13

At the zoo, there were 260 people at the panda exhibit. 30% of the people at the panda exhibit were visitors from China. How man

y people were visitors from China?
Mathematics
1 answer:
kondaur [170]3 years ago
6 0

First we convert percentage to a decimal:

30\%= \cfrac{30}{100}= \cfrac{3}{10}

Then we multiply the decimal and a number:

\cfrac{3}{10}\cdot260=\cfrac{3\cdot\not\!\!\!260^\ {26}}{\not\!\!10}=3\cdot26= \boxed{78}

Answer:

There were 78 visitors from China.

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I need help asap!!!!! pls you’ll earn brainlist
Anni [7]

Answer:

1 % decrease

Step-by-step explanation:

The percent of decrease time can be written as the expression \frac{200}{200}-\frac{198}{200} = \frac{2}{200}. Now, we convert the fraction into a decimal: \frac{2}{200} = \frac{1}{100} = 0.01. We can convert this decimal into a percentage: 0.01*100 = 1%.

<u><em>PLZ MARK BRAINLIEST!!!</em></u>

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4 years ago
My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the
AVprozaik [17]

Answer:

a) n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

b) n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.9=0.1 and \alpha/2 =0.05. And the critical value would be given by:  

z_{\alpha/2}=\pm 1.64  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.02 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

Part b

For this case since we don't have a prior estimate we can use \hat p =0.5

n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

8 0
3 years ago
Alvin is 14 years older than elga's The sum of their ages is 94 what is elga'ss age
Sonja [21]
Elga’s age is 40 and Alvin’s age is 54
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3 years ago
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Given uv = su tu sv prove vt = st
Lady bird [3.3K]

Answer:  see proof below

<u>Step-by-step explanation:</u>

\begin{array}{cl|cl}&\underline{\text{Statement}}&&\underline{\text{Reason}}\\1.&TU\perp SV&1.&\text{Given}\\2.&\angle TUV = 90^o&2.&\text{De finition of Perpendicular angles}\\&\angle TUS = 90^o&&\\3.&\angle TUV=\angle TUS&3.&\text{Transitive Property}\\4.&UV=US&4.&\text{Given}\\5.&TU=TU &5.&\text{Reflexive Property}\\6.&\triangle TUV = \triangle TUS&6.&\text{SAS Congruency Theorem}\\7.&VT=ST&7.&CPCTC\end{array}

5 0
4 years ago
Three less than twice a number is 15.
inessss [21]

Answer:

3-2x=15

Step-by-step explanation:

add 3 to both sides makes -2x=18. divide -2 from both side gets the answer x=-9, so the answer is C, -9

5 0
3 years ago
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