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Sergio [31]
3 years ago
7

Name a median for AABC.

Mathematics
1 answer:
vlada-n [284]3 years ago
3 0

Answer:

1st answer BD should be the right one because BD bisects angle ABC

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The scale factor of the blueprint of a wall to the actual wall is 0.07. The area of the actual wall is 36ft² what is the area of
ss7ja [257]

Answer:

The area of the wall on the blueprint is 0.1764 ft²

Step-by-step explanation:

The scale is the relationship that exists between the magnitudes of a drawing and the actual dimensions.

The scale factor is the ratio of the dimensions in two similar figures. The term "similar figures" refers to figures that have the same shape but different sizes.

 The ratio between areas is equal to the squared scale factor. This is,  the scale factor for areas is the squared scale factor,

To solve scale problems in this case, then the following proportion must be proposed:

\frac{representation area}{actual area} =scale factor^{2}

Being:

  • representation area=?
  • actual area=36 ft²
  • scale factor=0.07

Replacing:

\frac{representation area}{36 ft^{2} } =0.07^{2}

Solving:

representation area= 0.07²*36 ft²

representation area=0.1764 ft²

<u><em>The area of the wall on the blueprint is 0.1764 ft²</em></u>

4 0
4 years ago
The line of the equation are parallel, perpendicular,or neither y=2x+3. y=2x
m_a_m_a [10]
They are parallel to each other
5 0
4 years ago
What is the value of the expression below?<br> -8 + 19 + 8<br> 0<br> 11<br> 19<br> 35
Inga [223]

Answer:

19

Step-by-step explanation:

-8+8=0

0+19=19

Hope it helps.

8 0
3 years ago
4x - 5 = 2 - x<br> solve the equation
larisa [96]

the answer will be 7/5

7 0
4 years ago
Read 2 more answers
HELP. there are 45 coins consisting of nickels, dimes and quarter making a total of 7 dollars. the number of dimes exceeds the n
MA_775_DIABLO [31]

9514 1404 393

Answer:

  20

Step-by-step explanation:

Let n, d, q represent the numbers of nickels, dimes, and quarters, respectively. Then we have ...

  n + d + q = 45

  5n +10d +25q = 700

  n -d = -5

__

Using n=d -5, we can substitute into the first two equations:

  (d -5) +d + q = 45

  2d +q = 50 . . . . add 5, collect terms [eq4]

__

  5(d -5) +10d +25q = 700

  15d +25q = 725 . . . . . . . . . . add 25, collect terms [eq5]

Multiplying [eq4] equation by 3 and subtracting that from 2/5 of [eq5], we have ...

  (2/5)(15d +25q) -3(2d +q) = (2/5)(725) -3(50)

  6d +10q -6d -3q = 290 -150

  7q = 140 . . . . . . simplify

  q = 20 . . . . . . . . divide by 7

There are 20 quarters.

8 0
3 years ago
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