Question

A coffee cup collection includes four green cup, 8 blue cups, and two black cups. What is the probability of selection 2 black cups one after another one without replacement

Answer 1

The probability of selection 2 black cups one after another one without replacement is 1/91

What is the probability of selection 2 black cups one after another one without replacement?

The given parameters are:

Green = 4

Blue = 8

Black = 2

Given that the selection is without replacement, this means that the number of cups reduces when one is selected

So, we have:

P(2 Black cups) = P(Black) * P(Black)

This gives

P(2 Black cups) = 2/(4 + 8 + 2) * (2 - 1)/(4 + 8 + 2 - 1)

Evaluate

P(2 Black cups) = 2/14 * 1/13

This gives

P(2 Black cups) =  1/91

Hence, the probability of selection 2 black cups one after another one without replacement is 1/91

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