a model of a plane is made using a scale of 1:5 if the real length of a plane is 20m what is the length of the model?

Mathematics

2 answers:

schepotkina [342]3 years ago

6 0

Answer:

Step-by-step explanation:

1/5 of 20

ser-zykov [4K]3 years ago

5 0

Answer:

Step-by-step explanation:

you must scale down to size- 1 m in real life = 5 (unit) in the model

20/5= 40

hope this helps :)

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What is the answer to this question can you please answer right

Arada [10]

On Monday she made 50 throws.
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a) The increase is just how much more she made the next day.
56 - 50 = 6
She had an increase of 6 free throws.

b) To find the percent increase, all you do is divide the two numbers.
56/50 = 1.12
To change that into a percentage, either multiply it by 100 or move the decimal point two places to the right.
1.12 × 100 = 112
She had a 112% increase in her free throws.

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6 0

3 years ago

What is the coefficient of x2y3 in the expansion of (2x + y)5?

Zigmanuir [339]

Option C:

The coefficient of $x^{2} y^{3}$ is 40.

Solution:

Given expression:

$(2 x+y)^{5}$

Using binomial theorem:

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here $a=2 x, b=y$

Substitute in the binomial formula, we get

$(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}$

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}$