Answer:
I hope it will help you.....
Answer: Marry Christmas!
Step-by-step explanation:
Answer:
A = 3
B = 1
C = 2
D = 10
E = 2
F = Not listed
G = 1
Step-by-step explanation:
![\sqrt[3]{270x^5y^7} =\sqrt[3]{27*10x^5y^7}=3xy^2\sqrt[3]{10x^2y}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B270x%5E5y%5E7%7D%20%3D%5Csqrt%5B3%5D%7B27%2A10x%5E5y%5E7%7D%3D3xy%5E2%5Csqrt%5B3%5D%7B10x%5E2y%7D)
Answer:
(Choice A)
Juanita gets a strike next game.'
Step-by-step explanation:
Your question is obviously incomplete.
Complete question is:
Juanita and Nina are bowling together. The probability of Juanita getting a strike next game is 24%. The probability of Nina getting a strike next game is 0.17. Which of these events is more likely?
(Choice A)
Juanita gets a strike next game.'
(Choice B)
Nina gets a strike next game.
(Choice C)
Neither. Both events are equally likely.
Answer:
Probability of Juanita : P(J)= 24% => 0.24
probability of Nina getting a strike next game: P(N) = 0.17
As you can see 0.24 > 0.17 ----> P(J)>P(N)
Thus it can be concluded that Juanita gets a strike next game is more likely.
so, choice A
