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Naddika [18.5K]
2 years ago
14

Alonso goes on a kayaking trip that costs $50. At the end, he wants to tip the guide 15%. How much will the tip be?

Mathematics
2 answers:
xeze [42]2 years ago
8 0

Answer:

I believe that the tip would be $7.50

Step-by-step explanation:

Well I'm assuming that they want us to find 15% of 50. And 15% of 50 is 7.5

Meaning that the answer is A

qaws [65]2 years ago
6 0
The answer is A. $7.50
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We are given an isosceles triangle.

An isosceles triangle has corresponding angles of corresponding sides same.

<em>Therefore, other angle is also of (3x+7) degrees.</em>

(5x+13) and (3x+7) makes a linear pair.

Therefore,

(5x+13) + (3x+7)  = 180

5x +13 + 3x +7 = 180.

8x +20 = 180.

Subtracting 20 from both sides, we get

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8x = 160

Dividing both sides by 8, we get

<h3>x = 20.</h3><h3>Therefore, correct option is 3rd option. </h3>
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3 years ago
To simplify the following expression, which operation would you complete second?
Bingel [31]
Divide, the first operation is the parentheses and then division
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Which of the following numbers is NOT a solution<br> of the inequality 3x – 5&gt;_4x – 3 ?
Arte-miy333 [17]

Answer:

A)-1

Step-by-step explanation:

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3 years ago
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12345 [234]

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Match each of the trigonometric expressions below with the equivalent non-trigonometric function from the following list. Enter
Levart [38]

Answer:

Match each of the trigonometric expressions below with theequivalent non-trigonometric function from the following list.Enter the appropiate letter(A,B, C, D or E)in each blank

A . tan(arcsin(x/8))

B . cos (arsin (x/8))

C. (1/2)sin (2arcsin (x/8))

D . sin ( arctan (x/8))

E. cos (arctan (x/8))

These are the spaces to fill out :

.. ..........x/64 (sqrt(64-x^2))

.............x/sqrt(64+x^2)

.............sqrt(64-x^2)/8

..............x/sqrt(64-x^2)

..............8/sqrt(64+x^2)

A. ........tan(arcsin(x/8))  =......x/sqrt(64-x^2)

B .      cos (arsin (x/8))  ....sqrt(64-x^2)/8

Step-by-step explanation:

To solve this we have to find the missing sides to each of the triange discribed in prenthesis thus

A we have the sides of the triangle given by x, 8 and  \sqrt{8^{2} - x^{2} }or  \sqrt{64 - x^{2} }

thus tan(arcsin(x/8))  = \frac{x}{\sqrt{64 - x^{2} }}  =

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B

Here we have cos = adjacent/hypotenuse where adjacent side is \sqrt{64 - x^{2} } and hypothenuse = 8 we have \sqrt{64 - x^{2} }/8

B .      cos (arsin (x/8))  ....sqrt(64-x^2)/8

4 0
3 years ago
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