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yan [13]
3 years ago
14

which two points should the line of best fit go through to best represent the data in the scatter plot (1,16) and (2,15) (1,16)

and (6,1) (2,15) and (4,9) (5,8) and (6,1)​
Mathematics
2 answers:
Dmitry [639]3 years ago
7 0

Answer:

you need to make a graph and plot the points on it so you would do (x,y) and (1,16) so on the x axis it would be 1 and the y is 16!

Step-by-step explanation:

Hop this helped!

Rashid [163]3 years ago
6 0
You simply have to plot the point and draw a line that passes through most of them
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The tabulated value is less than the calculated value, therefore we accept the null hypothesis and It show that there is a difference in the mean overall distance of brands.

Step-by-step explanation:

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You put the names of all the students in your class in a paper bag. There are 19 boys and 12 girls. If you draw a name at random
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Answer:

19/31

Step-by-step explanation:

12+19=31

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A rectangle has width w and its length is 2 units shorter that 3 times the width
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2(3w-2+w)
=2(4w-2)
=8w-4

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Does the following table show a proportional relationship between the variables x and y? x 5/6 25/6 125/6 y 2 10 50
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Step-by-step explanation:

This table shows a proportional relationship between the variables x and y.

3 0
3 years ago
A manufacturer produces light bulbs that have a mean life of at least 500 hours when the production process is working properly.
denpristay [2]

Answer:

We conclude that the population mean light bulb life is at least 500 hours at the significance level of 0.01.

Step-by-step explanation:

We are given that a manufacturer produces light bulbs that have a mean life of at least 500 hours when the production process is working properly. The population standard deviation is 50 hours and the light bulb life is normally distributed.

You select a sample of 100 light bulbs and find mean bulb life is 490 hours.

Let \mu = <u><em>population mean light bulb life.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 500 hours      {means that the population mean light bulb life is at least 500 hours}

Alternate Hypothesis, H_A : \mu < 500 hours     {means that the population mean light bulb life is below 500 hours}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                           T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean bulb life = 490 hours

           σ = population standard deviation = 50 hours

           n = sample of light bulbs = 100

So, <u><em>the test statistics</em></u>  =  \frac{490-500}{\frac{50}{\sqrt{100} } }

                                     =  -2

The value of z test statistics is -2.

<u>Now, at 0.01 significance level the z table gives critical value of -2.33 for left-tailed test.</u>

Since our test statistic is higher than the critical value of z as -2 > -2.33, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis.</u>

Therefore, we conclude that the population mean light bulb life is at least 500 hours.

7 0
3 years ago
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