Two events are occurring:
1) Rolling a die
Sample Space = {1,2,3,4,5,6}
Total number of outcomes in sample space = 6
Favorable outcomes = Odd number
Number of Favorable outcomes = 3
Probability of getting an odd number = 3/6
2) Tossing a coin
Sample Space = {H, T}
Probability of getting a head= 1/2
The probability of getting odd number and head will be the product of two probabilities, which will be = 3/6 x 1/2 = 3/12
Thus there is 3/12 = 1/4 (0.25 or 25%) probability of getting an odd number and a head in given scenario.
So correct answer is option C
The answer is A. If the number of T-shirts is t, then you substitute the t in each equation and solve for all the numbers.
f(t)= 17+13t f(t)= 17+13t f(t)= 17+13t
f(t)= 17+13(12) f(t)= 17+13(17) f(t)= 17+13(22)
f(t)= 17+156 f(t)= 17+221 f(t)= 17+286
f(t)= 173 f(t)= 238 f(t)= 303
For the answer to the question above, I believe the answer is simply <u><em>8.
</em></u>
2 groups divided into four participants. So all in all people needed is 8.
I hope this helped you. Have a nice day!
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Yes, it is a function because each input has only one output.
Hope it helps!
Integration by parts will help here. Letting
and
, you end up with
and
. Now
For the remaining integral, setting
gives
, so
Putting everything together, you end up with