Answer:
The equation for the trend line would be y = -1/100x + 25
Step-by-step explanation:
In order to find the trend line, we first need to find the slope. To do so, we need to find two points on the line. The points we'll use are (0, 25) and (2500, 0). Next, we use the slope formula.
m(slope) = (y2 - y1)/(x2 - x1)
m = (0 - 25)/(2500 - 5)
m = -25/2500
m = -1/100
Now that we have this we can use the slope and the intercept in slope intercept form to model the trend line.
y = mx + b
y = -1/100x + 25
It would be 40. youd just add a zero to the end of each number and they add up to 250
Let the cost of gasoline in the year 2000 be represented b the equation
y = a + b*x
where
x = months, counted from January
y = cost, dollars
The given data in the table is
Month: Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec
x, months: 1 2 3 4 5 6 7 8 9 10 11 12
y, dollars: --- --- --- --- 1.76 2.13 --- --- --- --- --- ---
When x = 5, y = 1.76.
Therefore
a + 5b = 1.76 (1)
When x = 6, y = 2.13
Therefore
a + 6b = 2.13 (2)
Subtract equation (1) from (2).
a + 6b - (a + 5b) = 2.13 - 1.76
b = 0.37
From (1), obtain
a = 1.76 - 5b
= 1.76 - 5*0.37
= -0.09
The required equation is
y = 0.37x - 0.09
The graph shows the line, with the given data for May and June.
Answer: D. y = 0.37x - 0.09
Y= Mx+b
In the equation of a straight line,the slope is the number "m" that is multiplied on the x, and "b<span>" is the </span>y<span>-intercept (that is, the point where the line crosses the vertical </span>y<span>-axis).</span>