I wrote process on this picture I hope it’ll helpful to you
Answer:
166.5 m³
Step-by-step explanation:
Vcone = ⅓ × pi × r² × h
pi × r² × h = 3 × Vcone
Vcylinder = pi × r² × h
Vcylinder = 3 × Vcone
Vcylinder = 3 × 55.5 = 166.5 m³
The first thing you must do is to calculate the weight of the gravel (w) that the truck holds (7.5 yards³). So, you have:
If the weight of 1 yard³ is 1.48 tons, then the weight of 7.5 yards³ is:
w=7.5x1.48 tons
w=11.1 tons
The problem says that the gravel will be placed in containers that each hold 3.7 tons of gravel,so, If they need 1 cotainer to place 3.7 tons, how many containers they need to place 11.1 tons?
1 container-------3.7 tons of gravel
x-------11.1 tons of gravel
x=(11.1x1)/3.7
x=11.1/3.7
x=3 containers
H<span>ow many containers of this size are needed to hold all the gravel from one truck?
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The answer is: 3 containers.
Answer:
10/1 +54/-6
Step-by-step explanation:
Is this the answer?
Answer:
dissect the trapezium into a square and triangle. since the triangle is a right angled one the base is 17-7=10cm
the height is found using Pythagorean theorem to be 24cm i.e 26²=x²+10²,x=√(676-100),x=√576,x=24cn
area of trapezium is (1/2)(a+b)h
a is the shorter side and b the longer side
(1/2)*(7+17)24
=288cm²
