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3 years ago

8

Acidity is measured on the pH scale. The acidity of a substance is given by pH=−logH, where H is the concentration of Hydrogen i

ons. If a substance has a pH of 6, which equation could be used to find its H value?

2 answers:

frosja888 [35]3 years ago

8 0

Answer:

[H^+] = Antilog[-6]

Step-by-step explanation:

Even though the question is incomplete, let us try to correctly derive the equation used to find the hydrogen ion concentration.

pH=−log[logH^+]

-pH = log[H^+]

[H^+] = Antilog[-pH]

Since pH =6

The equation is;

[H^+] = Antilog[-6]

Olin [163]3 years ago

6 0

Answer:

logH=−6

Step-by-step explanation:

Substituting the given value into the formula: 6=−logH; −6=logH; 10−6=H; H=0.000001. The equation logH=−6 is a step in the process of finding the H value.

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The ﬁgure shows four types of quadrilaterals. What type of quadrilateral shown

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Trapezoid

Step-by-step explanation:

Note that the bases (top horizontal line segment and the bottom horizontal line segment) are <em>parallel</em> while the sides are congruent.

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3 years ago

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10x -15x + 5= -45 + 20

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Answer:

x=6

Step-by-step explanation:

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The washington family is having a new house built. they are trying to decide what type of material to use for the outside of the

Y_Kistochka [10]

2/5

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2 years ago

What is the equation of a line that is perpendicular to −x+3y=9 and passes through the point (−3, 2) ?

vekshin1

The equation of line that is perpendicular to the line $-x+3y =9$ and passes through the point $\left({-3,2}\right)$ is $\boxed{{\mathbf{y=-3x-7}}}$ .

Further explanation:

It is given that the equation of line is $-x+3y =9$ and passes through point $\left({-3,2}\right)$ .

Rewrite the given equation $-x+3y =9$ as follows:

$\begin{aligned}-x+3y&=9\\3y&=9+x\\y&=\frac{9}{3}+\frac{1}{3}x\\y&=\frac{1}{3}x+3\\\end{aligned}$

Now, compare the obtained equation of line $y=\frac{1}{3}x+3$ with the standard equation of line $y=mx+b$ .

$\begin{aligned}m&=\frac{1}{3}\\b&=3\\\end{aligned}$

Therefore, the slope is $\frac{1}{3}$ .

It is given that both lines are perpendicular to each other so the product of slope must be equal to $-1$ .

${m_1}\cdot {m_2}=-1$ …… (1)

Substitute $\frac{1}{3}$ for ${m_1}$ in equation (1) to obtain the value of slope ${m_2}$ .

$\begin{aligned}\frac{1}{3}\cdot{m_2}&=-1\\{m_2}&=-3\\\end{aligned}$

Therefore, the slope is $-3$ .

It is given that the line passes through point $\left({-3,2}\right)$ .

The point-slope form of the equation of a line with slope $m$ passes through point $\left({{x_1},{y_1}}\right)$ is represented as follows:

$y-{y_1}=m\left({x-{x_1}}\right)$ …… (2)

Substitute $-3$ for ${x_1}$ , $2$ for ${y_1}$ and $-3$ for $m$ in equation (2) to obtain the equation of line.

$\begin{aligned}y-2&=-3\left({x-\left({-3}\right)}\right)\\y-2&=-3\left({x+3}\right)\\y&=-3x-9+2\\y&=-3x-7\\\end{aligned}$

Therefore, the equation of line is $y=-3x-7$ .

Thus, the equation of line that is perpendicular to the line $-x+3y=9$ and passes through the point $\left({-3,2}\right)$ is $\boxed{{\mathbf{y=-3x-7}}}$ .

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Answer Details:

Grade: Junior High School

Subject: Mathematics

Chapter: Coordinate Geometry

Keywords: Coordinate Geometry, linear equation, system of linear equations in two variables, variables, mathematics, equation of line, line, passes through point.

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4 years ago

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Then p=3.<br> Use the equation k = 3n to find the value of k when n = 3.

Bad White [126]

Answer:

k = 9

Step-by-step explanation:

n = 3, so substitute 3 for n in the equation

k = 3(3)

k = 9

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3 years ago