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3 years ago

HELP ASAP Is this atom more likely to gain electrons or to lose electrons? Explain how you can tell.

Chemistry

1 answer:

Zina [86]3 years ago

6 0

It is more likely to gain electrons because it wants to achieve the “8 electron configuration”. So because it has 16 electrons it will gain 2 electrons more

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A cylinder at left with balls evenly spaced throughout the cylinder has an arrow leading to a cylinder at right cylinder with ba

Lelechka [254]

gas to liquid

Explanation:

The change of state indicated by this analogy is from gas to liquid.

Cylinder to the left is filled with gases

Cylinder to the right is made up of liquid.

Gases occupy the volumes of containers they are introduced into.
They are random and possess a high kinetic energy.
Liquids have definite volume and flow with one another.
The gases in A are dispersed and in random motion.
This phase change is called condensation

learn more:

Phase change brainly.com/question/1875234

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3 years ago

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Which value gives the number of particles in 1 mol of a substance?

d1i1m1o1n [39]

The answer is <span>6.02x 10^23.</span>

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4 years ago

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8. What coefficients would balance the following equation:

Orlov [11]

Answer:

Explanation:

1N2+3H2→ 2NH3

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3 years ago

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A 55.0g sample of iron (III) filings is reacted with 23.8g of powdered sulfur (S8). How much iron (III) sulfide in moles would b

Margaret [11]

Answer:

0.744 mol

Explanation:

the balanced equation for the reaction is

8Fe + S₈ ---> 8FeS

molar ratio of Fe to S₈ is 8:1

number of moles of Fe - 55.0 g / 56 g/mol = 0.98 mol

number of moles of S - 23.8 g / 256 g/mol = 0.093 mol

if we are to assume that S₈ is the limiting reactant

if 1 mol of S₈ reacts with 8 mol of Fe

then 0.093 mol of S₈ reacts with - 8 x 0.093 mol = 0.744 mol of Fe

however there's 0.98 mol of Fe present but only 0.744 mol of Fe is needed

therefore Fe is in excess and S₈ is the limiting reagent

molar ratio of S₈ to FeS is 1:8

then 0.093 mol of S₈ reacts with - 8 x 0.093 = 0.744 mol of FeS

number of FeS moles produced is 0.744 mol

8 0

3 years ago

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What is the OH- of {H+} = 4.0 x 10 to the power of -8

True [87]

Answer:

At standard room temperature, $[{\rm OH^{-}] \approx 2.5 \times 10^{-7}\; \rm M$ when $[{\rm H^{+}] = 4.0 \times 10^{-8}\; \rm M$ .

Explanation:

The following equilibrium goes on in water:

${\rm H_{2}O}\, (l) \rightleftharpoons {\rm H^{+}}\, (aq) + {\rm OH^{-}}\, (aq)$ .

The forward reaction is known as the self-ionization of water. The ionization constant of water, $K_{\rm w}$ , gives the equilibrium position of this reaction:

$K_{\rm w} = [{\rm H^{+}] \cdot [{\rm OH^{-}}]$ .

At standard room temperature ( $25\; {\rm ^{\circ}C}$ ), $K_{\rm w} \approx 10^{-14}$ . Also, $[{\rm H^{+}}] = 4.0 \times 10^{-8}\; \rm mol \cdot L^{-1}$ . Substitute both values into the equation and solve for $[{\rm OH^{-}}]$ .

$\begin{aligned} {[}{\rm OH^{-}}{]} &= \frac{K_{\rm w}}{[{\rm H^{+}}]} \\ &\approx \frac{10^{-14}}{4.0 \times 10^{-8}} = 2.5 \times 10^{-7}\end{aligned}$ .

In other words, in an aqueous solution at standard room temperature, $[{\rm OH^{-}] \approx 2.5 \times 10^{-7}\; \rm M$ when $[{\rm H^{+}] = 4.0 \times 10^{-8}\; \rm M$ .

5 0

3 years ago