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Contact [7]
3 years ago
13

What is the product of 3fe + 4h20 > fe3o4+4h2

Chemistry
1 answer:
Tju [1.3M]3 years ago
3 0

Ferrosoferric oxide and hydrogen gas are the products of this reaction.

<h3><u>Explanation:</u></h3>

Iron is the metallic element with the atomic number 26. It has a valency of both 2 and 3 which forms two types of oxide - ferrous oxide and ferric oxide.

Iron reacts with water with a metal and acid reaction, which forms both the iron oxide and evolves hydrogen gas. The hydrogen gas escapes the system and the mixture of iron oxide is left over in the system. The mixture is denoted by the formula Fe_3O_4 and is called ferrosoferric oxide.

This reaction is reversible and is reversed if hydrogen gas is passed over heated ferric oxide in increased pressure.

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How many grams of CO2 are produced from 6.7 L of O2 gas at STP?
Tasya [4]
<h3>Answer:</h3>

13 g CO₂

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

<u>Stoichiometry</u>

  • Using Dimensional Analysis

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>
<h3>Explanation:</h3>

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] 6.7 L O₂

[Solve] g O₂

<u>Step 2: Identify Conversions</u>

[STP] 22.4 L = 1 mol

[PT] Molar Mass of O: 16.00 g/mol

[PT] Molar Mass of C: 12.01 g/mol

Molar Mass of CO₂: 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 6.7 \ L \ O_2(\frac{1 \ mol \ O_2}{22.4 \ L \ O_2})(\frac{44.01 \ g \ O_2}{1 \ mol \ O_2})
  2. [DA] Divide/Multiply [Cancel out units]:                                                           \displaystyle 13.1637 \ g \ O_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

13.1637 g CO₂ ≈ 13 g CO₂

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