<u>Answer-</u>
<u>Solution-</u>
The equation for time period of a simple pendulum is given by,
Where,
T = Time period,
L = Length of the rod,
g = Acceleration due to gravity.
Frequency (f) of the pendulum is the reciprocal of its period, i.e
Putting the values,
Id say the answer to your question is c.25
Problem # 1
Not Factored: (5x^2 - 13x - 6)
Factored: (5x + 2 )(x - 3)
There is no real "work" to be shown for this, you can see that
1) Seperating 5x^2 into 5x and x will get you the equation in the form:
(5x ) (x ) = 5x^2 +
2) To complete this factor you need to guess which two numbers will add together to give you - 13x and multiply to form -6 (from the original unfactored equation). The numbers that will do this are 2 and 3
3) You can plug in negative or positives of those numbers to make sure they give you the exact results you need.
For example testing -2 and 3 you will get: (5x - 2) (x + 3 ) = 5(x^2) - 2x + 15x - 6 = 5x^2 +13x - 6. This is NOT the same as the unfactored equation. So you know -2 and 3 is the wrong choice. Choosing 2 and -3 will give you the answer instead.
As i said, there's no actual "work" to show this, you have to make guesses and try to factor it.
-------------------------------------------------------------------------------------------------
Problem # 2
Not Factored: 4x^4 - 28x^3 + 48x^2
Factored: 4x^2 (x^2 - 7x + 12) =
4x^2 (x - 3) (x - 4)
To solve this, you factor out the 4x^2 from the entire equation. Then you can further factor the quadratic equation by seperating x^2 into (x )(x ) and guessing for which numbers will add to -7x and multiply to 12
3.6% compounded quarterly=.036/4=0.009 per period
FV=5600(1+.009)^4y where FV=future value, and y is time, in years. So:
FV(6)=5600(1.009)^4(6)=5600(1.009)^24=$6943.46
☺☺☺☺
