All categories

2 years ago

The first term of an arithmetic sequence is 3. The common

Mathematics

1 answer:

aleksklad [387]2 years ago

5 0

Answer:

a1 (n-1) d

a1: 1st term

d: difference

hope it helps..please mark me brainliest..

thank you! have a good day ahead

You might be interested in

200 + 200m - 100 - 100m + 100

slava [35]

Answer:

200+100m

Step-by-step explanation:

Simplified by collecting like terms

5 0

2 years ago

2x^-7xy+3y^2 ÷2x^2-18y^2

Murrr4er [49]

Answer:

-x • (81x3y4 + 343x2y2 - 7938x - 3969y2)

———————————————————————

441

8 0

2 years ago

Read 2 more answers

HELP PLEASE ILL GIVE YOU 15 POINTS THANK YOU

sasho [114]

Answer:

X Y

4. 2

8. 3

12. 4

hope this is helpful for you

8 0

3 years ago

Read 2 more answers

15. If x=a Sin2t (I+Cos2t) and y=b Cos 2t (1-Cos2t) then find dy/dx at =22/7*4

Sav [38]

By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}$

It looks like we're given

$\begin{cases}x=a\sin(2t)(1+\cos(2t))\\y=b\cos(2t)(1-\cos(2t))\end{cases}$

where a and b are presumably constant.

Recall that

$\cos^2t=\dfrac{1+\cos(2t)}2$

$\sin^2t=\dfrac{1-\cos(2t)}2$

so that

$\begin{cases}x=2a\sin(2t)\cos^2t\\y=2b\cos(2t)\sin^2t\end{cases}$

Then we have

$\dfrac{\mathrm dx}{\mathrm dt}=4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t$

$\dfrac{\mathrm dy}{\mathrm dt}=-4b\sin(2t)\sin^2t+4b\cos(2t)\sin t\cos t$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{4b\cos(2t)\sin t\cos t-4b\sin(2t)\sin^2}{4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t}$

$\implies\boxed{\dfrac{\mathrm dy}{\mathrm dx}=\dfrac ba\tan t}$

where the last reduction follows from dividing through everything by $\cos(2t)\cos^2t$ and simplifying.

I'm not sure at which point you're supposed to evaluate the derivative (22/7*4, as in 88/7? or something else?), so I'll leave that to you.

8 0

3 years ago

Pls help explain if u can

Whitepunk [10]

Answer:

A dilation (similarity transformation) is a transformation that changes the size of a figure. It requires a center point and a scale factor , k . The value of k determines whether the dilation is an enlargement or a reduction.

In simple words, it's stretching, when you dilate with scale factor of x, means you multiply the previous value with x, say co-ordinates area -2,4, so you do (-2x,4x) to find the co-ordinates after dialation,

Here the scale factor is 3, so the new co-ordinates are,

(-2×3, 4×3) which is A' (-6, 12)

similarly,

B' (12, -3)

C' (-3, -6)

Answered by GAUTHMATH

5 0

3 years ago

Read 2 more answers