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3 years ago

11

Greatest common factor of 26m^4n^2, m^2n

1 answer:

Katyanochek1 [597]3 years ago

8 0

Step-by-step explanation:

Hey there!

Given;

$1st \: expn = 26 {m}^{4} {n}^{2}$

= 2*13 m⁴ n²

2nd expn = m² n

Therefore, greatest common factor is; m²n.

<u>Hope</u><u> it</u><u> helps</u><u>!</u>

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