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3 years ago

Right answer gets brainlist

Mathematics

1 answer:

andrew-mc [135]3 years ago

8 0

Answer:

Step-by-step explanation:

18(3)(22)=1188

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Evaluate 5-\dfrac{t}35−

solmaris [256]

Answer:

31.438

Step-by-step explanation:

yan ppo ang tama sagot

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Need help please I’m begging yeah.

Simora [160]

Answer: The answer is B.

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3 years ago

Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel

nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

$\theta=\frac{\pi}{3}$

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be= $r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j$

By using $cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}$

Force along the plane will be= $\mid F_x\mid=F\cdot r$

Force along the plane will be = $\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3$ N

By using $i\cdot i=j\cdoty j=k\cdot k=1,i\cdot j=j\cdot k=k\cdot i=j\cdot i=k\cdot j=i\cdot k=0$

Therefore, force along the plane= $\mid F_x\mid(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)$

2.The vector perpendicular to the plane= $r=-sin\frac{\pi}{3}-cos\frac{\pi}{3}=-\frac{\sqrt 3}{2}i-\frac{1}{2}j$

The force perpendicular to the plane= $\mid F_y\mid=F\cdot r=-8j(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

The force perpendicular to the plane= $4$ N

Therefore, $F_y=4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

Sum of two component of force= $F_x+F_y=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)+4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

Sum of two component of force= $2\sqrt 3i-6j-2\sqrt3 i-2j=-8j$

Hence,sum of two component of forces=Total force.

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3 years ago

I need help with six and seven plz

kolbaska11 [484]

Answer:

6) 102

7) 58

NOTE: Supplementary add to 180° and Complementary add to 90°

<u><em>Please mark as brainliest if answer is right </em></u>

Have a great day, be safe and healthy

Thank u

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3 years ago

The speed, s, of the current in a certain whirlpool is modeled by s=300/d, where d is the distance from the center of the whirlp

JulijaS [17]

For this case we have the following equation:
s = 300 / d
Where,
s: the speed of the current in a certain whirlpool
d: the distance from the center of the whirlpool
We have then that:
If the distance from the center of the whirpool is large, the speed is small.
If the distance from the center of the whirlpool is very small, the speed tends to infinity
Answer:
Large distance, small speed.
Short distance, speed tends to infinity.

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