Use simultaneous equations:
2x + 7 = x^2 + 8x - 9
7 = x^2 + 6x - 9
16 = x^2 + 6x
+ or - 4 = 7x
answer is
-4/7 or 4/7
Answer:
<u>D) (f o g)(x) = 10x² - 60x + 93</u>
Step-by-step explanation:
f(x) = 10x² + 3
g(x) = x - 3
⇒ (f o g)(x)
⇒ f(x - 3)
⇒ f(x - 3) = 10(x - 3)² + 3
⇒ f(x - 3) = 10(x² - 6x + 9) + 3
⇒ f(x - 3) = 10x² - 60x + 90 + 3
⇒ <u>(f o g)(x) = 10x² - 60x + 93</u>
Answer:
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Step-by-step explanation:1001010101001010101001010101010010101010101001010101010101010100101010101010101010101010101010000000000000000111111111110000000001010101001010101010
Answer:
2^4 or 16
Step-by-step explanation:
We know that a^b / a^c = a^(b-c)
2^9 / 2^5
2^(9-5)
2^4 or 16
We can begin by rearranging this into multiplication:
Now we can factor the numerators and denominators:
The factors
(x+4) and
(x+2) cancel out, leaving us with:
Our answer comes out to be:
or
Based on the numerator of the second fraction (since we used its inverse), the denominators of both, and the factors we canceled out earlier, the restrictions are
x ≠ -4, -3, -2, -1, 4
