The sum of 5 consecutive integers is 110<span>.
Hope it helps :)</span>
Answer:
B is the answer
Step-by-step explanation:
A = πr²
24π = πr²
24 = r²
24 = r²
= r
r = 
= 2
C = 2πr
C = 2π(2
)
C = 4
π
Answer:
C
Step-by-step explanation:
In this technique, if we have to factorise an expression like ax2+bx+c, we need to think of 2 numbers such that:
N1⋅N2=a⋅c=1⋅−12=−12
AND
N1+N2=b=−1
After trying out a few numbers we get N1=3 and N2=−4
3⋅−4=−12, and 3+(−4)=−1
x2−x−12=x2−4x+3x−12
x(x−4)+3(x−4)=0
(x+3)(x−4)=0
Now we equate the factors to zero.
x+3=0,x=−3
x−4=0,x=4