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fomenos
2 years ago
5

I need help I do not understand and am struggling

Mathematics
1 answer:
Kryger [21]2 years ago
3 0
It’s most likely they will pay with cash, because credit is the 2nd more done. It’s like a inference of what the person is going to pay with based on what people pay more on.
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The height, h, of a plant (in inches) w weeks since it was planted is represented by the equations h=3w+3. How many weeks will i
Hatshy [7]

Answer: 3 weeks

Step-by-step explanation:

We have to note firstly that 12 inches = 1 foot.

The equation given to represent the height in the question, h = 3w + 3.

The number of weeks that it will take the plant to reach one foot will then be:

h = 3w + 3

12 = 3w + 3

3w = 12 - 3

3w = 9

w = 9/3

w = 3

It'll take 3 weeks

7 0
3 years ago
Question (c)! How do I know that t^5-10t^3+5t=0?<br> Thanks!
astra-53 [7]
(a) By DeMoivre's theorem, we have

(\cos\theta+i\sin\theta)^5=\cos5\theta+i\sin5\theta

On the LHS, expanding yields

\cos^5\theta+5i\cos^4\theta\sin\theta-10\cos^3\theta\sin^2\theta-10i\cos^2\theta\sin^3\theta+5\cos\theta\sin^4\theta+i\sin^4\theta

Matching up real and imaginary parts, we have for (i) and (ii),


\cos5\theta=\cos^5\theta-10\cos^3\theta\sin^2\theta+5\cos\theta\sin^4\theta
\sin5\theta=5\cos^4\theta\sin\theta-10\cos^2\theta\sin^3\theta+\sin^5\theta

(b) By the definition of the tangent function,

\tan5\theta=\dfrac{\sin5\theta}{\cos5\theta}
=\dfrac{5\cos^4\theta\sin\theta-10\cos^2\theta\sin^3\theta+\sin^5\theta}{\cos^5\theta-10\cos^3\theta\sin^2\theta+5\cos\theta\sin^4\theta}

=\dfrac{5\tan\theta-10\tan^3\theta+\tan^5\theta}{1-10\tan^2\theta+5\tan^4\theta}
=\dfrac{t^5-10t^3+5t}{5t^4-10t^2+1}


(c) Setting \theta=\dfrac\pi5, we have t=\tan\dfrac\pi5 and \tan5\left(\dfrac\pi5\right)=\tan\pi=0. So

0=\dfrac{t^5-10t^3+5t}{5t^4-10t^2+1}

At the given value of t, the denominator is a non-zero number, so only the numerator can contribute to this reducing to 0.


0=t^5-10t^3+5t\implies0=t^4-10t^2+5

Remember, this is saying that

0=\tan^4\dfrac\pi5-10\tan^2\dfrac\pi5+5

If we replace \tan^2\dfrac\pi5 with a variable x, then the above means \tan^2\dfrac\pi5 is a root to the quadratic equation,

x^2-10x+5=0

Also, if \theta=\dfrac{2\pi}5, then t=\tan\dfrac{2\pi}5 and \tan5\left(\dfrac{2\pi}5\right)=\tan2\pi=0. So by a similar argument as above, we deduce that \tan^2\dfrac{2\pi}5 is also a root to the quadratic equation above.

(d) We know both roots to the quadratic above. The fundamental theorem of algebra lets us write

x^2-10x+5=\left(x-\tan^2\dfrac\pi5\right)\left(x-\tan^2\dfrac{2\pi}5\right)

Expand the RHS and match up terms of the same power. In particular, the constant terms satisfy

5=\tan^2\dfrac\pi5\tan^2\dfrac{2\pi}5\implies\tan\dfrac\pi5\tan\dfrac{2\pi}5=\pm\sqrt5

But \tanx>0 for all 0, as is the case for x=\dfrac\pi5 and x=\dfrac{2\pi}5, so we choose the positive root.
3 0
3 years ago
The angle of elevation from
weqwewe [10]

Answer:

104.5 ft

Step-by-step explanation:

In the picture I uploaded I showed all of the work so yeah!!! :)

5 0
3 years ago
Bob's youth group is selling candy bars for a fundraiser. The candy bars cost $2 each. To date, they have raised $700. Their goa
Brilliant_brown [7]
Hey need to sell 1200+ more because if they want more than $3100 and they already have $700 they need $2400 and divide that by 2.
7 0
3 years ago
Read 2 more answers
The sum of two numbers is 65 one is 4 times as large as the others.what are the numbers?​
bixtya [17]
<h3><em>Hey! </em></h3>

<u>let the numbers be n and m</u>

<u>n+m=65</u>

<u>n=4m</u>

<em>So when we put our work in:</em>

<u>4m+m=65</u>

<u>5m=65</u>

<u>m=13</u>

<u>n=52</u>

So therefore your two numbers are 52 and 13!

<em>Hope this helped! °ω°</em>

6 0
3 years ago
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