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3 years ago

Graph the following lines and write the equation in slope-intercept form.

Mathematics

1 answer:

Taya2010 [7]3 years ago

3 0

Answer:

y=mx+b

3=slope

1=y coordinate

-8=x coordinate

b=y intercept

Substitute m for 3

y=3x+b

Next, substitute the coordinate values

1=3(-8)+b

Solve

1=-24+b

+24 +24

25=b

Now substitute b and m for their respective values

y=3x+25

Step-by-step explanation:

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ra1l [238]

Answer:C

Step-by-step explanation:

x=4+√21,4−√21

Decimal Form:

8.58257569

0.58257569

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3 years ago

Jesse deposited $3600 in a new regular savings account that earns 6% annually in simple interest. How much is in the account aft

gayaneshka [121]

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Question 8 Find the unit vector in the direction of (2,-3). Write your answer in component form. Do not approximate any numbers

slamgirl [31]

Answer:

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

Step-by-step explanation:

Let be $\vec u = (2,-3)$ , its unit vector is determined by following expression:

$\hat {u} = \frac{\vec u}{\|\vec u \|}$

Where $\|\vec u \|$ is the norm of $\vec u$ , which is found by Pythagorean Theorem:

$\|\vec u\|=\sqrt{2^{2}+(-3)^{2}}$

$\|\vec u\| = \sqrt{13}$

Then, the unit vector is:

$\hat{u} = \frac{1}{\sqrt{13}} \cdot (2,-3)$

$\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

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3 years ago

What is the additive inverse of 0?

jenyasd209 [6]

Answer:

The additive inverse of 0 is 0.

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kap26 [50]

Integers are whole numbers so the answer is -3

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