The sum of two numbers is 131. One number is 6 more than 4 times the other. Which of the following is the smaller number
1 answer:
Answer: oop
Step-by-step explanation:
Let X = smaller number
Let Y = larger number
Sum of numbers is 130 ==> X + Y = 130 ==> Y = 130 - X
4 times the smaller subtracted from the larger is 10 ==>
Y - 4*X = 10
Substitute the value for Y in to the 2nd equation
(130 - X) - 4*X = 10
130 - 5*X = 10
-5*X = -120
X = 24
Y = 130 - 24 = 106
Check: 24 + 106 = 130
106 - 4*24 = 106 - 96 = 10
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Step-by-step explanation:
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Hope this helps :)
