Answer/Step-by-step explanation:
a. m<h = x°
Two angles to use in finding x are <h and 55°
Angle pair formed: linear pair angles
b. x° + 55° = 180° (linear pair)
Subtract 55° from each side
x + 55 - 55 = 180 - 55
x = 125°
c. Given: m<n = y°
Two angles to use in solving for y are: <h and <n
Angle pair formed: alternate exterior angles
d. m<n = y° (given)
m<n = x° = 125° (as solved in 2b)
Therefore:
y = x (alternate exterior angles are congruent)
thus:
y = 125° (substitution)
Answer: Option D
Step-by-step explanation:
Note that the projectile height as a function of time is given by the quadratic equation
To find the maximum height of the projectile we must find the maximum value of the quadratic function.
By definition the maximum value of a quadratic equation of the form
is located on the vertex of the parabola:
Where 
In this case the equation is:
Then
So:
Answer:
Option B, y = 2 Superscript x + 2 Baseline + 3
- Brainliest if this was helpful :)
Answer:
the expression would be 20h+25
Step-by-step explanation:
Answer:
12 and 18
Step-by-step explanation:
sum the parts of the ratio, 2 + 3 = 5
30 ÷ 5 = 6 ← value of 1 part of the ratio
2 parts = 2 × 6 = 12
3 parts = 3 × 6 = 18
The numbers are 12 and 18
