Answer:
Group A, because seven children have a forearm length longer than 10 inches
Step-by-step explanation:
Create the dot plots based on the given information (please see attached images).
Group A = blue dots
Group B = red dots
From inspection of the attached dot plots, we can see that Group A appears to have the longer average forearm length. This is because 7 children have a forearm length of longer than 10 inches.
To calculate the average forearm length, sum all data values and divide by the total number of data values.


Thus proving that Group A has the longer average former length.
A= 2 WL+ 2 LH+ 2 HW.
W= width
L= length
H= height
1/sin^2x-1/tan^2x=
1/sin^2x-1/ (sin^2x/cos^2x)<<sin tan= sin/cos>>
= 1/sin^2x- cos^2x / sin^2x
= (1- cos^2x) / sin^2x <<combining into a single fraction>>
sin^2 x / sin^2x <<since 1- cos^2 x sin^2 x
=1
this simplifies to 1.
Answer: 50,380m
Step-by-step explanation:
190m * 270m = 51,300m
23m * 40m = 920m
Because the barn is in the field, we subtract the barn's area from the field's area, which leaves us with
51,300m - 920m = 50,380m
Answer:
L = w+2
L+w = 60
W+2+w = 60
2w+2 = 60
W+1 = 30
W = 29
L = 31