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My name is Ann [436]

2 years ago

13

3 Fred is playing tennis. For every 2 of his serves that land in, 3 serves land out. If he hit 30 serves in, how many serves lan

ded out? A 90 B. 6 C. 180 D. 45

2 answers:

sineoko [7]2 years ago

6 0

Answer:

d

Step-by-step explanation:

2:3 = 30:45

blagie [28]2 years ago

4 0

2 serves in..............3serves out
30serves in...............x serves out

2x=30* 3
x=30*3/2= 45 serves out

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Answer:

7300 mL

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Remember 1000 mL = 1 L Multiply both sides by 7.3

7300 mL = 7.3 L

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3 years ago

There are 130 m&m's in a bag. there are half as many green as red. the number of blue is equal to the number of red and gree

AleksandrR [38]

Let x = red
Let 0.5x = green
Let (x) + (0.5x) = 1.5x = blue
Let 0.5(1.5x) = 0.75x = yellow
Let 0.75x + 4 = brown

$(x) + (0.5x) + (1.5x) + (0.75x) + (0.75 + 4) = 130$
$x + 0.5x+ 1.5x + 0.75x + 0.75 + 4 = 130$
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$4.5x = 126$
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Use this value to calculate the other required numbers.
red = 28
green = 0.5x = 0.5(28) = 14
blue = 1.5x = 1.5(28) = 42
yellow = 0.75x = 0.75(28) = 21
brown = 0.75x + 4 = 0.75(28) + 4 = 25

8 0

3 years ago

Activity: A flagpole has cracked 1.7 m from the ground and fallen over, as if hinged. The top of the flagpole hit the ground 3 m

Anastasy [175]

Answer:

Height of flagpole before it fell = 5.15 m

Step-by-step explanation:

Given:

Height of remain pole (p) = 1.7 m

Distance from base (b) = 3 m

Find:

Height of flagpole before it fell

Computation:

Using Pythagorean theorem

H = √ p² + b

Length of broken part = √ 1.7² + 3²

Length of broken part = √ 2.89 + 9

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8 0

3 years ago

A car travels 76 km in 47 minutes.

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47mins is 0.783 of an hour

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3 0

3 years ago

PLEASE HELP NEED THIS ANSWERED CORRECTLY

Helen [10]

f(3) = 1.9

Solution:

Given function:

$$f(x)=\frac{14}{7+2 e^{-0.6 x}}$

To find f(3):

Substitute x = 3 in the given function.

$$f(3)=\frac{14}{7+2 e^{-0.6 (3)}}$

$$f(3)=\frac{14}{7+2 e^{-1.8}}$

Let us first simplify $2e^{-1.8}$ .

Apply exponent rule: $a^{-b}=\frac{1}{a^{b}}$

$2e^{-1.8}=2\frac{1}{e^{1.8}}$

The value of $e^{1.8}=6.04964$ . (using calculator)

$$\frac{2}{e^{1.8}}=\frac{2}{6.04964}=0.33059$

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Substitute this value in f(3).

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$$f(3)=\frac{14}{7.33059}$

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Hence the value of f(3) is 1.9.

3 0

3 years ago