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nasty-shy [4]
3 years ago
12

Edward has 30 sweets.

Mathematics
2 answers:
posledela3 years ago
4 0

Answer:

12

Step-by-step explanation:

Sum the parts of the ratio, 2 + 3 = 5 parts

Divide the number of sweets by 5 to find the value of one part of the ratio

30 ÷ 5 = 6 sweets ← value of 1 part of the ratio, thus

2 × 6 = 12 ← number of red sweets

lianna [129]3 years ago
3 0

Answer:

20 red sweets

Step-by-step explanation:

do two thirds of 30 and the part that cane out is the red sweets

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Answer: B and E are irrational numbers

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Find the surface area of the following figure.
fgiga [73]

Answer:

\boxed{\textsf{\pink{ Hence the TSA of the cuboid is $\sf 32x^2$}}}.

Step-by-step explanation:

A 3D figure is given to us and we need to find the Total Surface area of the 3D figure . So ,

From the cuboid we can see that there are 5 squares in one row on the front face . And there are two rows. So the number of squares on the front face will be 5*2 = 10 .

We know the area of square as ,

\qquad\boxed{\sf Area_{(square)}= side^2}

Hence the area of 10 squares will be 10x² , where x is the side length of each square. Similarly there are 10 squares at the back . Hence their area will be 10x² .

Also there are in total 12 squares sideways 6 on each sides . So their surface area will be 12x² . Hence the total surface area in terms of side of square will be ,

\sf\implies TSA_{(cuboid)}= 10x^2+10x^2+12x^2\\\\\sf\implies\boxed{\sf TSA_{(cuboid)}= 32x^2}

Now let's find out the TSA in terms of side . So here the lenght of the cuboid is equal to the sum of one of the sides of 5 squares .

\sf\implies 5x = l \\\\\sf\implies x = \dfrac{l}{5} \\\\\qquad\qquad\underline\red{ \sf Similarly \ breadth }\\\\\sf\implies b = 3x  \\\\\sf\implies x = \dfrac{ b}{3}

\rule{200}2

Hence the TSA of cuboid in terms of lenght and breadth is :-

\sf\implies TSA_{(cuboid)}= 10x^2+10x^2+12x^2\\\\\sf\implies TSA_{(cuboid)}= 20\bigg(\dfrac{l}{5}\bigg)^2+12\bigg(\dfrac{b}{3}\bigg) \\\\\sf\implies TSA_{(cuboid)}= 20\times\dfrac{l^2}{25}+12\times \dfrac{b^2}{9}\\\\\sf\implies \boxed{\red{\sf TSA_{(cuboid)}= \dfrac{4}{5}l^2 +\dfrac{4}{3}b^2 }}

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2 years ago
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LuckyWell [14K]

Answer: the range would thus be [-3, 1/3].)

Step-by-step explanation:

1. To sketch the function f(x) = (2/3)x - 3, we first need to find two points that we can later join to sketch the line, for example the x- and y-intercepts.

a) The x-intercept occurs when f(x) = 0, so if f(x) = 0, then:

f(x) = (2/3)x - 3

0 = (2/3)x - 3

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We have now found the x-intercept at (9/2, 0)

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Now we know that the y-intercept is at (0, -3)

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Since there haven't been any constraints specified, we can say that both the Domain and Range are (-∞, ∞), since the graph continues forever both along the x- and y-axis.

(Note that this isn't always the case and would change if, for example, the question stipulated that there was a domain of [0, 5] and you had to find the range. Then, you would calculate the value of y at each end of the domain (if x = 0, y = -3 and if x = 5, y = 1/3) - in my example, the range would thus be [-3, 1/3].)

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