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melisa1 [442]
3 years ago
14

Which transformations could be performed to show that △ABC is similar to △A"B"C"?

Mathematics
2 answers:
Over [174]3 years ago
7 0

Answer:

D

Step-by-step explanation:

-Dominant- [34]3 years ago
4 0

Answer:

D

Step-by-step explanation:

Because I said so

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Math............................................
Alik [6]

Answer:A

Step-by-step explanation:IT IS BECAUSE EVERY X VALUE CORRESPONDS TO EVERY Y VALUE

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Solve for x and y!!
Evgen [1.6K]

Answer:

Step-by-step explanation:

4y - 16 + 68 = 180

4y + 52 = 180

4y = 128

y = 32

2x - 24 = 68

2x = 92

x = 46

8 0
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Can you simplify am • an. if so what is it
Inga [223]

Answer:

Yes a^2mn

Step-by-step explanation:

You do this by multiplication.

6 0
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Estimate 39 times 24<br> A. 8000<br> B. 14000<br> C. 800<br> D. 1400
valentinak56 [21]
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What is the length of the segment, endpoints of which are intersections of parabolas y=x^2− 11/4 x− 7/4 and y=− 7/8 x^2+x+ 31/8
kobusy [5.1K]

Answer:

The length of line segment is 5

Step-by-step explanation:

we are given equation of parabolas as

y=x^2-\frac{11}{4}x-\frac{7}{4}

y=-\frac{7}{8}x^2+x+\frac{31}{8}

Firstly, we will find intersection points

we can set them equal

and then we can solve for x

x^2-\frac{11}{4}x-\frac{7}{4}=-\frac{7}{8}x^2+x+\frac{31}{8}

Multiply all sides by 8

x^2\cdot \:8-\frac{11}{4}x\cdot \:8-\frac{7}{4}\cdot \:8=-\frac{7}{8}x^2\cdot \:8+x\cdot \:8+\frac{31}{8}\cdot \:8

8x^2-22x-14=-7x^2+8x+31

15x^2-30x-45=0

now, we can factor it

15(x^2-2x-3)=0

15(x-3)(x+1)=0

x=-1,x=3

now, we can find y-values

At x=-1:

y=(-1)^2-\frac{11}{4}(-1)-\frac{7}{4}

y=2

so, we get point as

(-1,2)

At x=3:

y=(3)^2-\frac{11}{4}(3)-\frac{7}{4}

y=-1

so, we get point as

(3,-1)

now, we can find distance between these two points

(-1,2)

x1=-1 , y1=2

(3,-1)

x2=3 , y2=-1

now, we can find distance

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

now, we can plug values

D=\sqrt{(3+1)^2+(-1-2)^2}

D=5

So,

The length of line segment is 5

6 0
3 years ago
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