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Answer:
The equation of the line would be y = 4/9x
Step-by-step explanation:
In order to find the equation, we first need to find the slope. We can do this by using the slope equation with the points.
m(slope) = (y2 - y1)/(x2 - x1)
m = (9 - 0)/(4 - 0)
m = 9/4
Now that we have this, we can use point-slope form along with one of the points to get the equation.
y - y1 = m(x -x1)
y - 0 = 4/9(x - 0)
y = 4/9x
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.
A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'
B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)
C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)
D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n
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* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.
The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
Answer:
23.4
Step-by-step explanation:
you use the equation for pythagorean theorem which is a^2+b^2=c^2 and plug in 12 and 18 into the a and b values to get 15^2+18^2=c^2 then you find the numbers squared so 225+324=c^2 add. 549=c^2 find square root. 23.4 rounded.
