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lianna [129]
2 years ago
15

Type the slope-intercept equation of the line that passes through the points (5,2) and (4,1). y = [? ]x + [ ]​

Mathematics
1 answer:
ivolga24 [154]2 years ago
5 0
The equation
y = mx + c
First let’s find m
m is the gradient
gradient is found with
rise/run

rise is the y run is x

So

y1 - y2 / x1 - x2

Can you do that
You might be interested in
Please help me this is very important
Virty [35]

Answer:

a. 24.5 $

b. 10.5 $

c. 7/10

Step-by-step explanation:

Given the original price of the sweater is: $ 35.

a) If you pay only $ \frac{7}{10} $ of the price, then the actual amount paid is: $ \frac{7}{10} \times 35 = \frac{49}{2} $ = 24.5 $.

b) Total amount Saved = Actual price - Price you paid

$ \implies $ Total Amount Saved = $ 35 - \frac{49}{2} $

$ = \frac{21}{2} $ = 10.5 $.

c) Fraction of the original price saved = Total amount Spent/Actual Price

$ \implies $ Total amount Saved = $ \frac{49}{2(35)} $

$ = \frac{49}{70} $ = $ \frac{7}{10} $

3 0
3 years ago
5/22 is that rational number
PIT_PIT [208]
Yes because 5/22 is 4 2/5 and that equals .4
3 0
2 years ago
Obtuse Triangles are _____ Iscoceles triangles
Annette [7]

Answer:

sometimes

Step-by-step explanation:

If this is an "always, sometimes, never" kind of problem, the answer is sometimes.

An isosceles triangle can be an obtuse triangle sometimes (but might be right or acute. An obtuse triangle can be isosceles or may be scalene. An obtuse triangle cannot be a right triangle nor equilateral.

The names for triangles comes from their angles:

right, acute, obtuse;

OR from their sides:

scalene, isosceles, equilateral.

4 0
2 years ago
Find the length of a segment with an endpoint of (2, 1) and a midpoint of (–2, –1).
Travka [436]

Answer:

Length of segment =4\sqrt5 units = 8.94 units

Step-by-step explanation:

Given:

End point of line: (2,1)

Midpoint of line: (-2,-1)

To find length of line segment.

Solution:

Distance from endpoint to midpoint is half the length of segment as the midpoint divides the line into equal halves.

Distance from end point to mid point can be found out using distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2)

Plugging in points for end point (2,1) and midpoint(-2,-1).

d=\sqrt{(-2-2)^2+(-1-1)^2)

d=\sqrt{(-4)^2+(-2)^2)

d=\sqrt{16+4)

d=\sqrt{20}

d=2\sqrt{5}

Length of half segment =2\sqrt{5} units

∴ Length of segment = 2\times length\ of\ half\ segment= 2\times 2\sqrt5=4\sqrt5 units

5 0
2 years ago
Does anyone know this?
Over [174]

Answer:

its TSU :)

your welcome

3 0
3 years ago
Read 2 more answers
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