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grigory [225]
3 years ago
14

Which number line represents the solution to 2.5 – 1.2x < 6.5 – 3.2x? A number line from negative 5 to 5 in increments of 1.

An open circle is at 4 and a bold line starts at 4 and is pointing to the left. A number line from negative 5 to 5 in increments of 1. An open circle is at 4 and a bold line starts at 4 and is pointing to the right. A number line from negative 5 to 5 in increments of 1. An open circle is at 2 and a bold line starts at 4 and is pointing to the left. A number line from negative 5 to 5 in increments of 1. An open circle is at 2 and a bold line starts at 4 and is pointing to the right.
Mathematics
2 answers:
olga55 [171]3 years ago
6 0

Answer:

Graph C

Step-by-step explanation:

Shkiper50 [21]3 years ago
5 0

Answer:

C. 2 is less than or equal to x

Step-by-step explanation:

E d g e n u i t y 2020

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Step-by-step explanation:

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5. A(Though it's position may change, reflective symmetry ensures that no other parts of the shape can change no matter what.)

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3 years ago
Pls help <br> What is side AC
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Answer:

tan●=opposite/adjacent

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2 years ago
Find k so that the distance from (–1, 1) to (2, k) is 5 units. k= k= *there are two solutions for 2*
dalvyx [7]

Answer:

k = -3

k =5

Step-by-step explanation:

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d = 5\\(-1,1) =(x_1,y_1)\\(2,k)=(x_2,y_2)\\

5=\sqrt{\left(2-\left(-1\right)\right)^2+\left(k-1\right)^2}\\\\\mathrm{Square\:both\:sides}:\quad 25=k^2-2k+10\\25=k^2-2k+10\\\\\mathrm{Solve\:}\:25=k^2-2k+10:\\k^2-2k+10=25\\\\\mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}\\k^2-2k+10-25=25-25\\k^2-2k-15=0\\\\\mathrm{Solve\:by\:factoring}\\\\\mathrm{Factor\:}k^2-2k-15:\quad \left(k+3\right)\left(k-5\right)\\\mathrm{Solve\:}\:k+3=0:\quad k=-3\\

\mathrm{Solve\:}\:k-5=0:\quad k=5\\\\k =5 , k=-3

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From least to greatest  ,0.5, 1.25, 1.4,1.95, 2.0 

7 0
4 years ago
Read 2 more answers
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