Answer:
what up my guy?
Step-by-step explanation:
Answer:
Step-by-step explanation:
We can get this done by using the code
def digits(n):
count = 0
if n == 0:
return 1
while (n > 0):
count += 1
n= n//10
return count
Also, another way of putting it is by saying
def digits(n):
return len(str(n))
------------------------------------------
print(digits(25)) # Should print 2
print(digits(144)) # Should print 3
print(digits(1000)) # Should print 4
print(digits(0)) # Should print 1
Doing this way, we've told the system to count the number of figures that exist in the number. If it's 1000 to 9999, then it records it as 4 digits. If it's 100 - 999, then it records it as 3 digits. If it's 10 - 99, it records as 2 digits. If it's 0 - 9, then it has to record it as a single digit.
Thanks
Answer:
2
Step-by-step explanation:
10a² : 5a² = 10 : 5 = 2
I'm assuming you meant to say a^3. If so, then
a^3 = a*a*a
a^3 = 5*5*5
a^3 = 125
Answer:
7/48,0.5,9/16,0.75
Step-by-step explanation:
Hope this helps
