Given
A rectangular park of length 60 m breadth 50 m encloses with volleyball court of length 18 m and breadth 10 m.
To find:
The area of the park excluding the court at the rate of Rs 110 per square meter.
Solution:
Area of a rectangle is:
Area of whole park is:
Area of volleyball court is:
Now, the area of the park excluding the court is:
Therefore, the area of the park excluding the court is 2820 square meter.
It is given that, B ≅ BC and AD ≅ CD
We need BD perpendicular to AC, then only we can say triangles AXB and CXB are congruent using the HL theorem.
If BD perpendicular to AC, means that AB and CB are the hypotenuse of triangles AXB and CXB respectively.
from the given information ABCD is a square
If BD and AC bisect each other then AX = CX
Then only we can immediately possible to prove that triangles AXD and CXD are congruent by SSS congruence theorem
Okay so 6.5% of $14.95 is 0.97175. That rounds to 0.97. And to get the total we just add 0.97 to 14.95. Our answer is 15.92. However if you don't want to round then you would add 14.95 and 0.97175 . This would give you15.92175. Hope this helps!
There are 60 minutes in one hour.
Divide 60 minutes by 10 minutes.
You get 6. That means you would need 6 recycled bottles to power a washing machine for one hour (that will be awesome if that were the case).
Have an awesome day! :)
Answer:
{x=2,y=2
Step-by-step explanation:
Equation 1:
Multiply both sides of the equation by a coefficient
{ 4(2x-y)=2*4
-5x+4y=-2
Apply Multiplicative Distribution Law
{8x-4y=2*4,-5x+4y=-2
8x-4y+(-5x+4y)=8+(-2)
Remove parentheses
8x-4y-5x+4y=8-2
Cancel one variable
8x-5x=8-2
Combine like terms
3x=8-2
Calculate the sum or difference
3x=6
Divide both sides of the equation by the coefficient of the variable
x=6/3
Calculate the product or quotient
x=2
Equation two:
{-5+4y=-2, x=2
-5*2+4y=-2
Calculate the product or quotient
-10+4y =-2
Reduce the greatest common factor (GCF) on both sides of the equation
-5+2y=-1
Rearrange unknown terms to the left side of the equation
2y=-1+5
Calculate the sum or difference
2y=4
Divide both sides of the equation by the coefficient of the variable
y=4/2
y=2
Hope this helps!!
