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Setler79 [48]
3 years ago
5

Solve (x-5)^2- 45 = 0, where x is a real number

Mathematics
1 answer:
sdas [7]3 years ago
5 0

Answer:

Step-by-step explanation: the answer is x= 3\sqrt{5} +5, -3 \sqrt{5} +5

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OLEGan [10]

Answer:

D) -2.14< root10 <|-2.8|

Step-by-step explanation:

the value for -2.14 is as plain as you can see, the negative version of 2.14.

The square root of 10 is 3.16227766.

The lines next to -2.8 is asking for the absolute value of -2.8, or the distance between that number and zero. The distance between -2.8 and 0 is positive 2.8, because distance can't be negative.

The 3 numbers taken from the explanations are -2.14, 3.16, and 2.8. Ranking them from least to greatest would give you -2.14, 2.8, 3.16, or -2.14< root10 <|-2.8|

7 0
3 years ago
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mel-nik [20]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!
Irina18 [472]

Answer:

x = 97.6

Step-by-step explanation:

cos = adjacent over hypotenuse

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* multiply each side by x *

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we're left with x = 97.63302055

Our last step is to round to the nearest tenth of a foot

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A 40% chance





Unless!
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please see the attached picture for full solution

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3 years ago
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