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Vsevolod [243]
3 years ago
8

The length of a rectangle is 5 inches less than twice its width. The perimeter of the rectangle is 60 inches. Which system of eq

uations can
be used to determine the length, L, and the width, W, of the rectangle?
Mathematics
1 answer:
nikdorinn [45]3 years ago
6 0

Answer:

Step-by-step explanation:

L=2W-5 and P=2(L+W) is the system

Substituting L=2W-5 into P=2(L+W) gives you

2(2W-5+W)=P=60

2(3W-5)=60

3W-5=30

3W=35

W=35/3, L=2W-5

L=55/3

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Answer: 4

<u>Step-by-step explanation:</u>

A = \frac{1}{2}r²θ

50 = \frac{1}{2}(5)²θ

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Answer: 1570.80 cm²

<u>Step-by-step explanation:</u>

A = \frac{1}{2}r²θ

A = \frac{1}{2}(100)²(\frac{\pi}{10})

A = 500π

A = 1570.80

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Answer: 19.63 m²

<u>Step-by-step explanation:</u>

A = \frac{1}{2}r²θ

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<u>Step-by-step explanation:</u>

\frac{\pi }{180} = \frac{\pi} {12x}

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<u>Step-by-step explanation:</u>

Quadrant I: 0° - 90°

Quadrant II: 90° - 180°

Quadrant III: 180° - 270°

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255° is in Quadrant III

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3 years ago
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Step-by-step explanation:

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7 0
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