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kupik [55]
2 years ago
8

Um how am I supposed to answer someone give me an example

Mathematics
2 answers:
babymother [125]2 years ago
7 0
This is how I answer my teachers for example: one thing you should know about me is that I am allergic to pollen my mom/dad told me about it it effects tho mostly during summer time :)
sweet [91]2 years ago
4 0

Answer:

I am allergic to pollen is causes me to become congested and my eyes to become watery nothing too severe. -Your friend, Bill Cipher

Step-by-step explanation:

You might be interested in
X= 7 4. Find the equation of a line passing through (5, -6) perpendicular (b) 3x + 5y = (d) 7x - 12y (f) x = 7 (a) 2x + y = 12 (
goldfiish [28.3K]

Given data:

The first set of equations are x+y=4, and x=6.

The second set of equations are 3x-y=12 and y=-6.

The point of intersection of first set of te equations is,

6+y=4

y=-2

The first point is (6, -2).

The point of intersection of second set of te equations is,

3x-(-6)=12

3x+6=12

3x=6

x=2

The second point is (2, -6).

The equation of the line passing through (6, -2) and (2, -6) is,

\begin{gathered} y-(-2)=\frac{-6-(-2)}{2-6}(x-6) \\ y+2=\frac{-6+2}{-4}(x-6) \\ y+2=x-6 \\ y=x-8 \end{gathered}

Thus, the required equation of the line is y=x-8.

6 0
10 months ago
How to solve -2p^2=16p+24
frozen [14]

Add  2p²  to each side of the equation.  Then you have

                 2p² + 16p + 24  =  0 .

Before you roll up your sleeves and start working on it, you can make it
even more convenient if you divide each side by  2 .  Then you have:

                 p² + 8p + 12 = 0 .

Now you have a nice, comfortable, familiar-looking quadratic equation. 
You can either factor the left side into  (p + 6) (p + 2), or, if you can't find
the factors, you can apply the quadratic formula to it.

That's how to solve it, and find its two solutions.


8 0
3 years ago
What is b in terms of a and c?
aev [14]

Answer:

b=\sqrt{c^2-a^2}

Step-by-step explanation:

The given relation is

c=\sqrt{a^2+b^2}

To make b the subject, we square both sides of the equation to get;

c^2=(\sqrt{a^2+b^2})^2

c^2=a^2+b^2

Isolate b on one side of the equation;

c^2-a^2=b^2

Or

b^2=c^2-a^2

We take the positive square root of both sides to get;

b=\sqrt{c^2-a^2}

6 0
3 years ago
Will mark as brainliest! 40 points! Thanks!
n200080 [17]

When given a system of equations, the "solutions" are defined where two equations intersect, or meet.


A. The point where the lines p(x) and g(x) meet is (3, -1), and thus this is considered the solution set.

B. Because there are three lines in total, g(x) is able to intersect both lines one time, and so it has two pairs of solutions.

The first is (3, -1), which has already been established with p(x).

The second is (0, 5), and this is where it intersects with f(x).

C. The solution to f(x) = g(x) is 0, as this is the only x value where both equations are equal.


Hope my answer helped!

6 0
2 years ago
Read 2 more answers
Z=y+mx. Solve for x. I need the answer fast
Simora [160]
If you want x, rearrange <span>Z=y+mx as follows:  mx = z - y.  Then div. all 3 terms by m:
        z-y
x = -------    (answer).
          m </span>
8 0
3 years ago
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