Given data:
The first set of equations are x+y=4, and x=6.
The second set of equations are 3x-y=12 and y=-6.
The point of intersection of first set of te equations is,
6+y=4
y=-2
The first point is (6, -2).
The point of intersection of second set of te equations is,
3x-(-6)=12
3x+6=12
3x=6
x=2
The second point is (2, -6).
The equation of the line passing through (6, -2) and (2, -6) is,
Thus, the required equation of the line is y=x-8.
Add 2p² to each side of the equation. Then you have
2p² + 16p + 24 = 0 .
Before you roll up your sleeves and start working on it, you can make it
even more convenient if you divide each side by 2 . Then you have:
p² + 8p + 12 = 0 .
Now you have a nice, comfortable, familiar-looking quadratic equation.
You can either factor the left side into (p + 6) (p + 2), or, if you can't find
the factors, you can apply the quadratic formula to it.
That's how to solve it, and find its two solutions.
Answer:
Step-by-step explanation:
The given relation is
To make 
the subject, we square both sides of the equation to get;
Isolate on one side of the equation;
Or
We take the positive square root of both sides to get;
When given a system of equations, the "solutions" are defined where two equations intersect, or meet.
A. The point where the lines p(x) and g(x) meet is (3, -1), and thus this is considered the solution set.
B. Because there are three lines in total, g(x) is able to intersect both lines one time, and so it has two pairs of solutions.
The first is (3, -1), which has already been established with p(x).
The second is (0, 5), and this is where it intersects with f(x).
C. The solution to f(x) = g(x) is 0, as this is the only x value where both equations are equal.
Hope my answer helped!
If you want x, rearrange <span>Z=y+mx as follows: mx = z - y. Then div. all 3 terms by m:
z-y
x = ------- (answer).
m </span>
