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Gelneren [198K]
4 years ago
12

We’ve all heard of acid rain and its impact on the environment, the infrastructure, like roads and buildings, and on humans. If

basic rain was a commonly occurring form of precipitation, what impact do you think it would have on the environment, the infrastructure, and on humans? Would it be more detrimental than or not as detrimental as acid rain? Explain your reasoning.
Chemistry
1 answer:
Ksivusya [100]4 years ago
6 0
It would be more beneficial than acid rain because it is non-corrosive. Its pH is neutral. It would help to dilute acid and alkaline materials and would wash away impurities. Animals, including humans, can drink pure water, but acid rain is harmful. Plants and the soil can accept pure water which aid in supplying plants with water they can absorb directly, and water can dissolve certain nutrients that can then be more readily absorbed by plants, vegetation and microbes living in the soil. Pure water can be stored (reservoir) without the need for filtering or purifying, so reducing costs in providing drinking water. Pure water is part of the natural cycle. It evaporates leaving no deposit.
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A 1.0-L buffer solution is 0.10 M in HF and 0.050 M in NaF. Which action destroys the buffer? (a) adding 0.050 mol of HCl (b) ad
Volgvan

Answer:

(a) adding 0.050 mol of HCl

Explanation:

A buffer is defined as the mixture of a weak acid and its conjugate base -or vice versa-.

In the buffer:

1.0L × (0.10 mol / L) = 0.10 moles of HF -<em>Weak acid-</em>

1.0L × (0.050 mol / L) = 0.050 moles of NaF -<em>Conjugate base-</em>

-The weak acid reacts with bases as NaOH and the conjugate base reacts with acids as HCl-

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<em>(a) adding 0.050 mol of HCl:</em> The addition of 0.050moles of HCl produce the reaction of 0.050 moles of NaF producing HF. That means after the reaction, all NaF is consumed and you will have in solution just the weak acid <em>destroying the buffer</em>.

(b) adding 0.050 mol of NaOH: The NaOH reacts with HF producing more NaF. Would be consumed just 0.050 moles of HF -remaining 0.050 moles of HF-. Thus, the buffer <em>wouldn't be destroyed</em>.

(c) adding 0.050 mol of NaF: The addition of conjugate base <em>doesn't destroy the buffer</em>

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