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Gelneren [198K]
3 years ago
12

We’ve all heard of acid rain and its impact on the environment, the infrastructure, like roads and buildings, and on humans. If

basic rain was a commonly occurring form of precipitation, what impact do you think it would have on the environment, the infrastructure, and on humans? Would it be more detrimental than or not as detrimental as acid rain? Explain your reasoning.
Chemistry
1 answer:
Ksivusya [100]3 years ago
6 0
It would be more beneficial than acid rain because it is non-corrosive. Its pH is neutral. It would help to dilute acid and alkaline materials and would wash away impurities. Animals, including humans, can drink pure water, but acid rain is harmful. Plants and the soil can accept pure water which aid in supplying plants with water they can absorb directly, and water can dissolve certain nutrients that can then be more readily absorbed by plants, vegetation and microbes living in the soil. Pure water can be stored (reservoir) without the need for filtering or purifying, so reducing costs in providing drinking water. Pure water is part of the natural cycle. It evaporates leaving no deposit.
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a concentration solution of H2so4 is 59.4% by mass (m/m) and has a density of 1.83 g/mL. How many mL of the solution would be re
Blababa [14]

Answer: 41.5 mL

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

Given : 59.4 g of H_2SO_4 in 100 g of solution  

moles of H_2SO_4=\frac{\text {given mass}}{\text {molar mass}}=\frac{59.4g}{98g/mol}=0.61

Volume of solution =\frac{\text {mass of solution}}{\text {density of solution}}=\frac{100g}{1.83g/ml}=54.6ml

Now put all the given values in the formula of molality, we get

Molality=\frac{0.61\times 1000}{54.6ml}=11.2M

To calculate the volume of acid, we use the equation given by neutralisation reaction:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of stock acid which is H_2SO_4

M_2\text{ and }V_2 are the molarity and volume of dilute acid which is H_2SO_4

We are given:

M_1=11.2M\\V_1=mL\\M_2=0.30M\\V_2=1550mL

Putting values in above equation, we get:

11.2\times V_1=0.30\times 1550\\\\V_1=41.5mL

Thus 41.5 mL of the solution would be required to prepare 1550 mL of a .30M solution of the acid

4 0
3 years ago
What is the formula mass for sodium chloride?
Zigmanuir [339]
Atomic mass of sodium is 22.9 g/mol
atomic mass of chloride is 35.45 g/mol
sodium chloride is 22.99 + 35.45= 58.44 g/mol
3 0
3 years ago
2 HCl + 1 Zn -> 1 H2 + ZnCl2 what type of reaction is this
Salsk061 [2.6K]

Answer:

Single replacement reaction

Explanation:

3 0
3 years ago
On the reaction side there are two or more reactants, and on the product side there is only one product. The reaction type is __
Grace [21]
It is a.combination that is the correct answer i think

3 0
3 years ago
The diagram below show an enlarged view of the beams of a triple-beam balance
VLD [36.1K]

Answer:

1) 455.2 g. 2) 545.2 g.

Explanation:

i think this is right

6 0
3 years ago
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