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Gelneren [198K]
3 years ago
12

We’ve all heard of acid rain and its impact on the environment, the infrastructure, like roads and buildings, and on humans. If

basic rain was a commonly occurring form of precipitation, what impact do you think it would have on the environment, the infrastructure, and on humans? Would it be more detrimental than or not as detrimental as acid rain? Explain your reasoning.
Chemistry
1 answer:
Ksivusya [100]3 years ago
6 0
It would be more beneficial than acid rain because it is non-corrosive. Its pH is neutral. It would help to dilute acid and alkaline materials and would wash away impurities. Animals, including humans, can drink pure water, but acid rain is harmful. Plants and the soil can accept pure water which aid in supplying plants with water they can absorb directly, and water can dissolve certain nutrients that can then be more readily absorbed by plants, vegetation and microbes living in the soil. Pure water can be stored (reservoir) without the need for filtering or purifying, so reducing costs in providing drinking water. Pure water is part of the natural cycle. It evaporates leaving no deposit.
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Answer:

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Explanation:

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3 years ago
Which group of lists below is made up of only pure substances?
german

Answer:

the answer is compounds

5 0
2 years ago
Which of the following combinations will result in a reaction that is spontaneous at all temperatures?
Katen [24]

Answer:

\huge\boxed{Option \ 2}

Explanation:

A reaction is spontaneous at all temperatures by the following combinations:

=> A negative enthalpy change ( \triangle H < 0 )

=> A positive entropy change ( \triangle S > 0 )

See the attached file for more better understanding!

8 0
3 years ago
Read 2 more answers
Unit: Stoichiometry
Reika [66]

Answer:

1. 2.41 × 1023 formula units

2. 122 L

3. 7.81 L

Explanation:

1. Equation of the reaction: 2 Na(NO3) + Ca(CO3) ---> Na2(CO3) + Ca(NO3)2

Mole ratio of NaNO3 to CaCO3 = 2 : 1

Moles of CaCO3 = mass/molar mass

Mass of CaCO3 = 20 g; molar mass of CaCO3 = 100 g

Moles of CaCO3 = 20 g/100 g/mol = 0.2 moles

Moles of NaNO3 = 2 × 0.2 moles = 0.4 moles

1 Mole of NaNO3 = 6.02 × 10²³ formula units

0.4 moles of NaNO3 = 0.4 × 6.02 × 10²³ = 2.41 × 1023 formula units

2. Equation of reaction : 2 H2O ----> 2 H2 + O2

Mole ratio of oxygen to water = 1 : 2

At STP contains 6.02 × 10²³ molecules = 1 mole of water

6.58 × 10²⁴ molecules = 6.58 × 10²⁴ molecules × 1 mole of water/ 6.02 × 10²³ molecules = 10.93 moles of water

Moles of oxygen gas produced = 10.93÷2 = 5.465 moles of oxygen gas

At STP, 1 mole of oxygen gas = 22.4 L

5.465 moles of oxygen gas = 5.465 moles × 22.4 L/1 mole = 122 L

3.Equation of reaction: 6 K + N2 ----> 2 K3N

Mole ratio of Nitrogen gas and potassium = 6 : 1

Moles potassium = mass/ molar mass

Mass of potassium = 90.0 g, molar mass of potassium = 39.0 g/mol

Moles of potassium = 90.0 g / 39.0 g/mol = 2.3077moles

Moles of Nitrogen gas = 2.3077 moles / 6 = 0.3846 moles

At STP, 1 mole of nitrogen gas = 22.4 L

0.3486 moles of oxygen gas = 0.3486 moles × 22.4 L/1 mole = 7.81 L

7 0
3 years ago
Refer to the electron distribution to answer 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s¹. What would be the period or series number of
Salsk061 [2.6K]

Answer:

C.5

Explanation:

A number of electrons present in valence shell of penultimate Shell represents the group of elements.

For s block elements: no.of group=number of valence shell electron.

p block elements: no. of group= 2 + 10 + number of valence electrons.

d block elements: no. of group= number(n-1)d electrons + number of electrons in nth shell.

Here, the differential electron is in p orbital hence, it belongs to p block

No. of group= 2+ 10 + 3=15 i.e 15th group or VA group.

5 0
3 years ago
Read 2 more answers
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