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timurjin [86]
3 years ago
6

This part insulates the reaction chamber from the transfer of heat to or from the surrounding environment. a.b.c.

Chemistry
2 answers:
gizmo_the_mogwai [7]3 years ago
7 0

The correct answers are:

1. This part insulates the reaction chamber from the transfer of heat to or from the surrounding environment. C

2. This part contains a known amount of water, which is placed there before the experiment starts. B

3. This part is where the metal is placed at the beginning of the experiment. B

4. This part is used for measuring the initial and final temperatures of the water. A

Correct on Edg.enuity/E2020

|Huntrw6|

Fiesta28 [93]3 years ago
4 0

Answer:

C

B

B

A

Explanation:

  1. This part insulates the reaction chamber from the transfer of heat to or from the surrounding environment. (C)
  2. This part contains a known amount of water, which is placed there before the experiment starts. (B)
  3. This part is where the metal is placed at the beginning of the experiment. (B)
  4. This part is used for measuring the initial and final temperatures of the water. (A)

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What is the mass percent of oxygen (0) in SO2?
vazorg [7]

Answer:

D. (16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%

Explanation:

Step 1: Detemine the mass of O in SO₂

There are 2 atoms of O in 1 molecule of SO₂. Then,

m(O) = 2 × 16.0 g = 16.0 g + 16.0 g = 32.0 g

Step 2: Determine the mass of SO₂

m(SO₂) = 1 × mS + 2 × mO = 1 × 32.1 g + 2 × 16.0 g = 32.1 g + 16.0 g + 16.0 g = 64.1 g

Step 3: Detemine the mass percent of oxygen in SO₂

We will use the following expression.

m(O)/m(SO₂) × 100%

(16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%

5 0
3 years ago
Type the correct answer in each box.
Arturiano [62]

Answer:

5SiO2 + 2CaC2 = 5Si + 2CaO + 4CO2

Explanation:

balancing equations is a lot of trial and error. My strategy to approaching this equation was to get the O's balanced. After trying several combonations I found that I needed 10 O's on each side of the equation for the other elements to match up. After I balanced the O's, I balanced my C's to 4 on each side. Then I balanced my Ca's to have 2 on each side. And last but not least I balanced my Si to have 5 on each side.

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3 years ago
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kati45 [8]

Answer:

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Explanation:

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7 0
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3 years ago
Sulfuric acid reacts with aluminum hydroxide by double replacement. if 34 g of sulfuric acid react with 33 g of aluminum hydroxi
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Answer is: sulfuric acid is the limiting reactant.
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m(H₂SO₄) = 34 g.
n(H₂SO₄) = m(H₂SO₄) ÷ M(H₂SO₄).
n(H₂SO₄) = 34 g ÷ 98 g/mol.
n(H₂SO₄) = 0,346 mol.
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n(Al(OH)₃) = 0,423 mol.
From chemical reaction: n(H₂SO₄) : n(Al(OH)₃) = 3 : 2.

4 0
4 years ago
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