Answer:
(a) 16-2x
(b)-x-2 or x+6
(c)
Step-by-step explanation:
(a)
|6-x|+|x-10|,
|4-x|=4-x,so x<4
|2-x|=x-2=-(2-x)
2-x<0
2<x
or x>2
2<x<4
so |6-x|=6-x,in 2<x<4
|x-10|=-(x-10),in 2<x<4
|6-x|+|x-10|=6-x-(x-10)=6-x-x+10=16-2x
(b)
2-|2-|x-2||,if x<-2
|x-2|=-(x-2) if x<-2
=2-|2-{-(x-2)}|
=2-|2+x+2|
x<-2
x+2<0
=2-|x+4|
=2-(x+4),if x>-4,or -4<x<-2
=2-x-4
=-x-2
if x<-4
then |x+4|=-(x+4)
2-|x+4|=2-{-(x+4)}
=2+x+4
=x+6
The Cold War 1945-<span>The Cold War 1945-1970</span>
Not so sure about the second one, but the first one is pretty simple:
The area of a circle = pi x radius^2
Since you need to find the area of the entire dvd, I'm assuming they mean if the hole in the center wasn't there, so add that to the diameter.
12+1.5 = 13.5
Half of the diameter is the radius, so half of 13.5 = 6.75
Now, multiply pi (3.14) by the radius, but have the radius squared. You'd write the equation like this:
3.14 x 6.75^2 (or on paper, the ^2 would be a small two diagonal from the 5)
Actual answer: 143.06625
You can round that to 143.
<span><span>
The correct answers are:</span><span>
(1) The vertical asymptote is x = 0
(2) The horizontal asymptote is y = 0
</span><span>
Explanation:</span><span>(1) To find the vertical asymptote, put the denominator of the rational function equals to zero.
Rational Function = g(x) = </span></span>

<span>
Denominator = x = 0
Hence the vertical asymptote is x = 0.
(2) To find the horizontal asymptote, check the power of x in numerator against the power of x in denominator as follows:
Given function = g(x) = </span>

<span>
We can write it as:
g(x) = </span>

<span>
If power of x in numerator is less than the power of x in denomenator, then the horizontal asymptote will be y=0.
If power of x in numerator is equal to the power of x in denomenator, then the horizontal asymptote will be y=(co-efficient in numerator)/(co-efficient in denomenator).
If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.
In above case, 0 < 1, therefore, the horizontal asymptote is y = 0
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