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morpeh [17]
3 years ago
5

6 ÷ 3 + 32 · 4 − 2 A. 36 B. 98 C. 22 D. 42

Mathematics
1 answer:
otez555 [7]3 years ago
4 0

Answer:128

Step-by-step

2+ 32 x 4-2

2+128-2

=128

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Susan and Steven are cousins. The sum of their ages is 33. The difference between three times Steven's age and half of Susan's a
VARVARA [1.3K]
The complete question is
Susan and Steven are cousins. The sum of their ages is 33. The difference between three times Steven's age and half of Susan's age is 36. Find <span>the age of Susan and Steven

let
x-----> </span>Susan's age
y---->  Steven's age

we know that
y+x=33-----> equation 1
3y-x/2=36----> multiply by 2----> 6y-x=72----> equation 2
adds equation 1 and equation 2

y+x=33
6y-x=72
-------------+
7y=105--------> y=15
x=33-y----> x=33-15----> x=18

the answer is
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Steven's age is 15

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Refer to the map shown in Exercise 2. If m∠1 is 64˚, what is the measure of ∠2?
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<h2>Explanation:</h2><h2></h2>

Hello! Remember you have to write complete questions in order to get good and exact answers. Here you haven't provided any figure, so I'll assume m∠1 and m∠2 are complementary angles. Angles that add up to 90° are called complementary angles. In this case, we know m∠1 and want to know m∠2. Thus, we can establish the following formula:

m∠1 + m∠2 = 90°

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m∠2 = 26°

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3 years ago
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