Answer:
Given:
n = 15
c = 95% = 0.95
Let us assume:
α = 0.05
Determine the difference in value of each pair.
→See attached for the table←
→See attached for the for the workings←
Result
a) There is sufficient evidence to reject the claim that the two methods provide the same mean value for natural vibration frequency.
b) (-10.9646, -0.0068)
Add the numbers and divide by 5 to get a mean of 6.4
8 - 6.4 = 1.6
4 - 6.4 = -2.4
7 - 6.4 = 0.6
8 - 6.4 = 1.6
5 - 6.4 = -1.4
Add the absolute value of each: 1.6 + 2.4 + 0.6 + 1.6 + 1.4 = 7.6
Divide by 5 = 1.52
1.5
Answer:
(x-3)^2=5=>
(x-3)=±square root of 5
x=+sqr.root5+3 or x=-sqr.root5+3
Explanation:
There may be a couple of reasons for this:
1. Each team represents a sample of the players in the league. The averages of (random) samples can be expected to have a standard deviation that is smaller than the population standard deviation by a factor related to sample size.
2. A team average will result from the players who are played the most. Each team can be expected to field players more often whose averages are among the highest. The standard deviation of a set of the top tier of players will necessarily be smaller than the standard deviation of the set of all players.
Answer: 5in
Step-by-step explanation:
1/3x8/8=8/24
1/8x3/3=3/24
8-3=5
