The change in enthalpy associated with the change in the water’s temperature is 1254 J.
<h3>What is specific heat?</h3>
The amount of heat required to increase the temperature of one gram of a substance by one Celsius degree is known as specific heat.
Enthalpy change will be calculated as:
ΔH = -cmΔT, where
m = mass of water = 50g
c = specific heat of water = 4.18J/g°C
ΔT = change in temperature = 28 - 22 = 6 °C
On putting values in the above equation, we get
ΔH = -(4.18)(50)(6) = -1254 J
Hence change in enthalpy of the reaction is -1254 J.
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B should be 20 because only 1 oxygen goes into water
C is hydrogen because 2 hydrogens go into each water
Can't read anything beyond c
Answer:
B : 0.133 M
Explanation:
moles Li3N3 = 0.4 mol Li x (2 moles Li3N/6 moles Li) = 0.133 M
